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zloy xaker [14]
3 years ago
7

PLEASE I NEED HELP ASAP!!!?

Mathematics
1 answer:
Slav-nsk [51]3 years ago
5 0

Answer:

11√3-7√6

im good at these, just hit me up if you need more help ;)

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The distributive property combines (blank) and (blank) to make multiplying whole numbers simpler.
just olya [345]
The distributive property combines (a single term) and (two or more terms) to make multiplying whole numbers simpler

hope this helps
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3 years ago
Ingnore question 17 but i need help 30 POINTS!!!
algol [13]
Not sure why they put the x bit

ok so know this:
AGE=HGB=CHG=FHD
and
AGH=EGB=CHF=GHD
and
AGE+AGH=180


11.
AGE=FHD=30

12.
AGH=CHF=150

13.
CHF=BGE=110

14.
CHG+HGA=180
CHG+120=180
CHG=60

15.
BHG=3x=AGE=CHG=FHD
not sure, but if we did use the fact that BGH+DHG=180 and BGH=3x and DHG=2x+50 then BHG=78 degrees

16.
GHD=2x+50=CHF=EGB=AGH, if we use facts above then GHD=102 degrees
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3 years ago
What can 23/40 be simplified by?
kicyunya [14]
23/40 can't be simplified as it has no common factors
8 0
3 years ago
​58.​Anna and Maya are competing in a dance tournament where dance moves are worth a certain number of points. If a dance move i
Charra [1.4K]
225 + 75 - 30 + ?
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3 years ago
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In a study of cell phone usage and brain hemispheric​ dominance, an Internet survey was​ e-mailed to 6965 subjects randomly sele
vladimir1956 [14]

The hypothesis test shows that we reject the null hypothesis and there is sufficient evidence to support the claim that the return rate is less than 20%

<h3>What is the claim that the return rate is less than 20% by using a statistical hypothesis method?</h3>

The claim that the return rate is less than 20% is p < 0.2. From the given information, we can compute our null hypothesis and alternative hypothesis as:

\mathbf{H_o :p =0.2}

\mathbf{H_i:p < 0.2}

Given that:
Sample size (n) = 6965

Sample proportion \mathbf{\hat p = \dfrac{x}{n} = \dfrac{1302}{6965} \sim0.1869}

The test statistics for this data can be computed as:

\mathbf{z = \dfrac{\hat p - p}{\sqrt{\dfrac{p(1-p)}{n}}}}

\mathbf{z = \dfrac{0.1869 -0.2}{\sqrt{\dfrac{0.2(1-0.2)}{6965}}}}

\mathbf{z = \dfrac{-0.0131}{0.0047929}}

z = -2.73

From the hypothesis testing, since the p < alternative hypothesis, then our test is a left-tailed test(one-tailed.

Hence, the p-value for the test statistics can be computed as:

P-value = P(Z ≤ z)

P-value = P(Z ≤ - 2.73)

By using the Excel function =NORMDIST (-2.73)

P-value = 0.00317

P-value ≅ 0.003

Therefore, we can conclude that since P-value is less than the significance level at ∝ = 0.01, we reject the null hypothesis and there is sufficient evidence to support the claim that the return rate is less than 20%

Learn more about hypothesis testing here:

brainly.com/question/15980493

#SPJ1

3 0
1 year ago
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