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Flauer [41]
2 years ago
15

Simple Quadratic Equation help please! worth 50 points :) ill be giving brainliest

Mathematics
2 answers:
likoan [24]2 years ago
8 0

Answer:

The answer is x= 3,2

Step-by-step explanation:

So the equation can be written in the form of (x+a)*(x+b)

Where (x+a),(x+b) are factors of the equation.

So by expanding we get x^2+(a+b)x+ab.

By comparing the above equation with the given equation we get a+b=5, ab= 6

We know that (a-b)^2=(a+b)^2–4ab

So we get (a-b)^2=(5)^2–4(6)

(a-b)^2=25–24

(a-b)^2=1

(a-b)=+1 or -1

So a-b=+1 or -1

So a+b=5 and let a-b=1

Adding both equations we get 2a=6

So a=3 and substituting a in the above one of the equation we get b=2

Similarly by taking a-b=-1we get

a=2 and b=3

So the factors of the given equation are

(x+2) and (x+3)

GuDViN [60]2 years ago
7 0

Answer:

x= -2 or -3

Step-by-step explanation:

Let's solve your equation step-by-step.

x^2+5x+6=0

Step 1: Factor left side of equation.

(x+2)(x+3)=0

Step 2: Set factors equal to 0.

x+2=0 or x+3=0

x=−2 or x=−3

just a rough estimate!

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steposvetlana [31]

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\dfrac{f+g}{f-g}=(f+g):(f-g)=\dfrac{2x^2-97}{(x+9)(x+4)}:\dfrac{65}{(x+9)(x+4)}\\\\=\dfrac{2x^2-97}{(x+9)(x+4)}\cdot\dfrac{(x+9)(x+4)}{65}\\\\Answer:\ \boxed{\dfrac{f+g}{f-g}=\dfrac{2x^2-97}{65}}

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Andreas93 [3]

Answer:

<em><u>1.c</u></em>

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3 years ago
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MrMuchimi

Answer:

6z + 9

Step-by-step explanation:

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distribute 3/4 by 12 to get 9

4 0
2 years ago
Question 2(Multiple Choice Worth 5 points)
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it C Step 2, the exponents in the denominator are added during multiplication

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joja [24]
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