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Westkost [7]
3 years ago
11

Identify the vertex of the graph. Tell whether it is a minimum or maximum.

Mathematics
1 answer:
Olegator [25]3 years ago
4 0

Answer:3333333333333333Step-by-step explanation:

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The volume of a cube is V= S^3 where V is the volume and s is the length of one side what is the volume of a cube if the length
sammy [17]

The volume of cube is 1000 cubic feet

<em><u>Solution:</u></em>

Given that,

<em><u>The volume of cube is given by formula:</u></em>

V = s^3

Where,

V is the volume of cube

"s" is the length of one side

<em><u>What is the volume of a cube if the length of a side s is 10 feet</u></em>

Given, s = 10 feet

<em><u>Substitute s = 10 in given formula,</u></em>

V = 10^3\\\\V = 10 \times 10 \times 10\\\\V = 1000

Thus volume of cube is 1000 cubic feet

7 0
3 years ago
Tim has two spinners , spinnerA and spinner B. Each spinner can only land on red or blue . The probability that spinner A will l
Ganezh [65]

Answer:

52

Step-by-step explanation:

<u>Spinner A</u>

  • Probability of red = 0.5,
  • Probability of blue = 0.5

<u>Spinner B</u>

  • Probability of red = 0.6,
  • Probability of blue = 0.4

<u>Probability of both A and B land on red: </u>

  • 0.5*0.6= 0.3

<u>Number of attempts to get outcome of 84 red on both spinners is:</u>

  • 84/0.3= 260

<u>Probability of both spinners land on blue:</u>

  • 0.5*0.4= 0.2

<u>Estimated number of both spinners land on blue:</u>

  • 260*0.2= 52  
4 0
3 years ago
Please help me here dudes and dudettes
BabaBlast [244]

Answer:

what!!!!!!!!!!!!!!!!!! so only for dudesssssssss

6 0
2 years ago
What is the product?
fredd [130]

Answer:

\frac{4k + 2}{k^{2}-4 }  ×  \frac{k-2}{2k+1}   =  \frac{2}{k + 2}

Step-by-step explanation:

\frac{4k + 2}{k^{2}-4 }  ×  \frac{k-2}{2k+1}

To solve the above, we need to follow the steps below;

4k+2 can be factorize, so that;

4k +2 = 2 (2k + 1)

k² - 4  can also be be expanded, so that;

k² - 4 = (k-2)(k+2)

Lets replace  4k +2  by  2 (2k + 1)

and

k² - 4 by  (k-2)(k+2)   in the expression  given

\frac{4k + 2}{k^{2}-4 }  ×  \frac{k-2}{2k+1}

\frac{2(2k+ 1)}{(k-2)(k+2)}   ×  \frac{k-2}{2k+1}

(2k+1) at the numerator will cancel-out (2k+1) at the denominator, also (k-2) at the numerator will cancel-out (k-2) at the denominator,

So our expression becomes;  

\frac{2}{k + 2}

Therefore, \frac{4k + 2}{k^{2}-4 }  ×  \frac{k-2}{2k+1}   =  \frac{2}{k + 2}

3 0
3 years ago
Read 2 more answers
I really need help please
Pepsi [2]

Answer:

Step-by-step explanation:

bb, ,llllllllllllllllllllllllllll

3 0
2 years ago
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