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sergij07 [2.7K]
3 years ago
5

A state lottery game consists of choosing one card from each of the four suits in a standard deck of playing cards. (There are 1

3 cards in each suit.)
Count the number of ways in which four cards, each of a different face value, can be chosen.
ways
Mathematics
1 answer:
ivolga24 [154]3 years ago
8 0

Answer:

17160

Step-by-step explanation:

first there are 13 options

then there are 13 - 1 that was chosen

then there are 13 - 2 that were chosen

then there are 13 - 3 that were chosen

so that's 13 options, then 12 options, then 11 options, and then 10 options

and in order to figure out all of the possibilties we mutiply the options so

13*12*11*10 = 17160

little further explaining of why this works:

we have a set of letters (3 in a set)

A B C

what are the possible combinations?

AB

AC

BC

BA

CA

CB

the answer is 6 which is also 3 * 2 * 1 = 6

HOPE THAT HELPS!1! ^_^

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The outdoor furniture center buys wooden benches for $50 each. The furniture store owner adds a %200 markup to the cost of the b
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Hope I helped u
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A newspaper reports the median house price is $250,000. From that standard, tell what you know about housing prices.
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Given that cot θ = 1/√5, what is the value of (sec²θ - cosec²θ)/(sec²θ + cosec²θ) ?
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Step-by-step explanation:

\mathsf{Given :\;\dfrac{{sec}^2\theta - co{sec}^2\theta}{{sec}^2\theta + co{sec}^2\theta}}

\bigstar\;\;\textsf{We know that : \large\boxed{\mathsf{{sec}\theta = \dfrac{1}{cos\theta}}}}

\bigstar\;\;\textsf{We know that : \large\boxed{\mathsf{co{sec}\theta = \dfrac{1}{sin\theta}}}}

\mathsf{\implies \dfrac{\dfrac{1}{cos^2\theta} - \dfrac{1}{sin^2\theta}}{\dfrac{1}{cos^2\theta} + \dfrac{1}{sin^2\theta}}}

\mathsf{\implies \dfrac{\dfrac{sin^2\theta - cos^2\theta}{sin^2\theta.cos^2\theta}}{\dfrac{sin^2\theta + cos^2\theta}{sin^2\theta.cos^2\theta}}}

\mathsf{\implies \dfrac{sin^2\theta - cos^2\theta}{sin^2\theta + cos^2\theta}}

Taking sin²θ common in both numerator & denominator, We get :

\mathsf{\implies \dfrac{sin^2\theta\left(1 - \dfrac{cos^2\theta}{sin^2\theta}\right)}{sin^2\theta\left(1 + \dfrac{cos^2\theta}{sin^2\theta}\right)}}

\bigstar\;\;\textsf{We know that : \large\boxed{\mathsf{cot\theta = \dfrac{cos\theta}{sin\theta}}}}

\mathsf{\implies \dfrac{1 -cot^2\theta}{1 + cot^2\theta}}

\mathsf{Given :\;cot\theta = \dfrac{1}{\sqrt{5}}}

\mathsf{\implies \dfrac{1 - \left(\dfrac{1}{\sqrt{5}}\right)^2}{1 + \left(\dfrac{1}{\sqrt{5}}\right)^2}}

\mathsf{\implies \dfrac{1 - \dfrac{1}{5}}{1 + \dfrac{1}{5}}}

\mathsf{\implies \dfrac{\dfrac{5 - 1}{5}}{\dfrac{5 + 1}{5}}}

\mathsf{\implies \dfrac{5 - 1}{5 + 1}}

\mathsf{\implies \dfrac{4}{6}}

\mathsf{\implies \dfrac{2}{3}}

<u>Hence</u><u>,</u><u> option</u><u> </u><u>(</u><u>a)</u><u> </u><u>2</u><u>/</u><u>3</u><u> </u><u>is </u><u>your</u><u> </u><u>correct</u><u> </u><u>answer</u><u>.</u>

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Murrr4er [49]
In the first step when the student did -2x-3 they didn’t make the sign positive. It should be 4=-2+6, not 4=-2-6
8 0
3 years ago
Read 2 more answers
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