Question

Jan 258:00:56 AM

Answer 1

Answer:

The equation of the straight line in point-slope form

                            $y - 4 = \frac{7}{9} (x-0)$

The equation of the straight line

                         7x -9y +36 =0

Step-by-step explanation:

Step(i):-

Given that the points (0,4) and (-9,-3)

The slope of the line

         $m = \frac{y_{2} - y_{1} }{x_{2}- x_{1} } = \frac{-3-4}{-9-0} = \frac{7}{9}$

Step(ii):-

    Equation of the straight line passing through the point (0,4) and having slope m = 7/9

          $y - y_{1} = m (x-x_{1} )$

         $y - 4 = \frac{7}{9} (x-0)$

      9 y - 36 = 7x

              9y = 7x + 36

          $y = \frac{7x}{9} +\frac{36}{9}$

Slope - intercept form  

                            $y = \frac{7x}{9} +4$

Final answer:-

The equation of the straight line in point-slope form

                            $y - 4 = \frac{7}{9} (x-0)$

The equation of the straight line

                         7x -9y +36 =0