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ruslelena [56]
2 years ago
7

Which expression is equivalent to 5(x + 9)? 5x + 9 5x + 45 x + 45 x + 9

Mathematics
1 answer:
nevsk [136]2 years ago
5 0

Answer:

5x+45

Step-by-step explanation:

It would be 5x+45 because

5*x=5x

5*9=45

5x+45

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Rashid [163]

The price of the Xbox One after tax is $265

<h3><u>Solution:</u></h3>

The price of a Xbox one is $250

The tax on Xbox one is 6%  

Now, the tax of 6% on 250 is calculated as follows:-

=\frac{6}{100} \times 250\\\\=\frac{250 \times 6}{100}=\frac{1500}{100}=15

So, the tax on Xbox one is $15

The total price of box including tax can be calculated by adding price of box and tax on box

<em>Total price of Xbox after tax = actual price of the Xbox One  + Tax on the Xbox One </em>

= $250 + $15

= $265

Hence, the price of the Xbox One after tax is $265

3 0
3 years ago
Help me solve the out and inputs of the table
velikii [3]
The in is -5 the out for 7 is -21 the out for -3 is 9the infor 15 is -5 the out for -10 is 30
5 0
3 years ago
Select the correct answers (there are more than one that are correct)​
Liono4ka [1.6K]

Answer:

its really good luck for you know what is not my phone

4 0
3 years ago
please help me and explain. what is the value of <img src="https://tex.z-dn.net/?f=%20%5Cfrac%7Bx%7D%7By%7D%20" id="TexFormula1"
rosijanka [135]
\frac{28}{x^2} = \frac{7}{xy}
multiplying both sides by x^2
28=\frac{7x^2}{xy}
simplifying
28= \frac{7x}{y}
dividing by 7
\frac{28}{7}= \frac{x}{y}
8 0
3 years ago
The scores on the LSAT are approximately normal with mean of 150.7 and standard deviation of 10.2. (Source: www.lsat.org.) Queen
faltersainse [42]

Answer:

a=150.7 -0.385*10.2=146.773

So the value of height that separates the bottom 35% of data from the top 65% (Or the 35 percentile) is 146.7.  

Step-by-step explanation:

1) Previous concepts

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".

The Z-score is "a numerical measurement used in statistics of a value's relationship to the mean (average) of a group of values, measured in terms of standard deviations from the mean".  

2) Solution to the problem

Let X the random variable that represent the  scores on the LSAT of a population, and for this case we know the distribution for X is given by:

X \sim N(150.7,10.2)  

Where \mu=150.7 and \sigma=10.2

We want to find a value a, such that we satisfy this condition:

P(X>a)=0.65   (a)

P(X   (b)

Both conditions are equivalent on this case. We can use the z score again in order to find the value a.  

As we can see on the figure attached the z value that satisfy the condition with 0.35 of the area on the left and 0.65 of the area on the right it's z=-0.385. On this case P(Z<-0.385)=0.35 and P(Z>-0.385)=0.65

If we use condition (b) from previous we have this:

P(X  

P(z

But we know which value of z satisfy the previous equation so then we can do this:

Z=-0.385

And if we solve for a we got

a=150.7 -0.385*10.2=146.773

So the value of height that separates the bottom 35% of data from the top 65% (Or the 35 percentile) is 146.7.  

5 0
3 years ago
Read 2 more answers
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