Answer:
0.048m
Step-by-step explanation:
Given:
<span>19, 25, 35, 38, 41, 49, 50, 52, 99
Just upon looking at the data set, I can determine that there is an OUTLIER. An outlier is a point that is distant from other points.
The outlier in this data set is number 99.
These data set has the following five number summary:
1) minimum number - 19
2) 1st quartile - 30
3) 2nd quartile or median - 41
4) 3rd quartile - 51
5) maximum number - 99
Interquartile range = q3 - q1 </span>→ 51 - 30 = 21
To determine if an observation point is an outlier, we need to determine the lower fence and the upper fence.
lower fence = q1 - 1.5(iqr)
lower fence = 30 - 1.5(21) → 30 - 31.5 = -1.5
upper fence = q3 + 1.5(iqr)
upper fence = 51 + 1.5(21) → 51 + 31.5 = 82.50
Any number outside the lower fence, -1.5, and upper fence, 82.50, is an OUTLIER.
99 is beyond the upper fence. Thus, it is an outlier.
Answer:
x = 5
Step-by-step explanation:
We have the algebraic expression and are asked to solve for x.
To solve, we need to isolate x.
2x + 22 = 4(x + 3)
Distribute :
2x + 22 = (4(x) + 4(3))
2x + 22 = 4x + 12
Subtract 12 from both sides :
2x + 10 = 4x
4x = 2x + 10
Subtract 2x from both sides :
2x = 10
Divide 2 from both sides to get x alone :
x = 5
Answer:
Total amount in Joe's savings account T = $448
Step-by-step explanation:
Given;
time t = 3 years
Annual rate r = 4%
Principal P = $400
Simple interest can be expressed as;
I = Prt/100
Substituting the given values;
I =400×4×3/100 = 4800/100
I = $48
Total amount in account T;
T = P + I = $400 + $48 = $448
