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Anit [1.1K]
3 years ago
7

Which 2 number can be divided into 2.5 and 11.2

Mathematics
1 answer:
malfutka [58]3 years ago
6 0

Answer:

2.5 would be 5 while 11.2 would be 22.4

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Apply the distributive property to create an equivalent expression 5x (-20 - 4) =
Bingel [31]

Answer:

-120x

Step-by-step explanation:

3 0
3 years ago
5m-8=2m+2 <br><br> what does m equal
vesna_86 [32]

Answer:

m = 10/3

<em>(as a decimal: m = 3.333...)</em>

<em />

Step-by-step explanation:

5m - 8 = 2m + 2

 5m - 8 = 2m + 2

- 2m       - 2m              <em>(make all "m" on one side to isolate variable)</em>

 3m - 8 = 2    

      + 8 + 8              <em>(get m entirely on 1 side)</em>

3m = 10

÷3      ÷3                         <em>(divide by 3 to get 1m)</em>

m = 10/3

<em>(as a decimal: m = 3.333...)</em>

<em />

<em />

hope this helps!! have a lovely day :)

5 0
2 years ago
If m &gt; n, which inequalities must be true? Check all that apply.
ololo11 [35]

Step-by-step explanation:

m > n         <em>add 2.1 to both sides</em>

m + 2.1 > n + 2.1         TRUE

m > n      <em>subtract (-4) from both sides</em>

m - (-4) > n - (-4)       TRUE

m > n       <em>add 16.5 to both sides</em>

16.5 + m > 16.5 + n     TRUE

m > n → 3 + m > n       <em>logic</em>

3 + m > n       <em>add 6 to both sides</em>

9 + m > 6 + n         TRUE

8 0
3 years ago
Read 2 more answers
A dog and a cat are 200 meters apart when they see each other. The dog can run at a speed of 30 meter per second, while the cat
LenKa [72]

Answer:

They'll meet after 200 meters , if they simultaneously start running towards each other.

Step-by-step explanation:

Let x =distance travelled by dog and 200-x be the distance travelled by cat. Inorder to meet, the sum of their travelled distances shall be equal to 200 meters as they are far apart by 200 meters.

Dog: Distance =Speed x time: x=30t

Cat: Distance = 200-x

=24t

The sum of their distance travelled shall be 200 meters: 30t+ 24t= 200;54t=200;t=200/54=3.7secs

So they will meet after 3.7 seconds

To check:

Distance travelled by dog :x=30(3.7)

=111.11 meters

Distance travelled by cat: 24t=24(3.7)

=88.89 meters

Therefore since they are travelling towards each other and their distance apart is 200 meters, after 3.7 seconds they will meet because dog travelled 111.11 meters and cat travelled 88.89 meters and they covered already 200 meters as the sum of 111.11+ 88.89

=200 meters

6 0
2 years ago
What is the fraction and decimal for 71%
Nadusha1986 [10]
The fraction is : 71/100
The decimal is : 0.71
3 0
4 years ago
Read 2 more answers
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