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3 years ago

Assume that y varies directly with x. If y= 2/5 when x= 1/3, find y when x = 1/4

Mathematics

1 answer:

astraxan [27]3 years ago

7 0

Step-by-step explanation:

y1/x1=y2/x2

2/5÷1/3=y÷1/4

y=3/10=0.3

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1. Given the equation y = -3x + 2.5

valentina_108 [34]

Answer:

a. when x=1 so substitute 1 to any X in the given equation.

y=-3(1)+2.5

y=-3+2.5

y=-0.5

b.when x is -1.5 so substitute -1.5 to any x in the equation

y=-3(-1.5)+2.5

y=-4.5+2.5

y=-2

4 0

3 years ago

When a certain tree was first planted, it was 4 feet tall, and the height of the tree increased by a constant amount each year f

MA_775_DIABLO [31]

Answer:

Option D is the correct answer.

Step-by-step explanation:

Initial height = 4 feet

Given that the height of the tree increased by a constant amount each year for the next 6 years. At the end of the 6th year, the tree was 1/5th taller than it was at the end of the 4th year.

Let the rate of growing each year be g.

After 6 years height of tree = 4 + 6g

After 4 years height of tree = 4 + 4g

At the end of the 6th year, the tree was 1/5th taller than it was at the end of the 4th year.

That is

$4+6g=4+4g+\frac{4+4g}{5}\\\\4+6g=\frac{20+20g+4+4g}{5}\\\\20+30g=24+24g\\\\6g=4\\\\g=\frac{2}{3}ft/year$

Option D is the correct answer.

8 0

3 years ago

Plz solve this question. you don't have to solve step by step but just give me some hints

levacccp [35]

Answer:

u have to use derieved form of formula of sin and cos

8 0

3 years ago

What is the area of the composite figure?

Rudik [331]

I have uploaded a link! The answer is in the link below:

http://www.vegetablefacts.net/vegetable-history/history-of-butthole/

4 0

3 years ago

A random sample of size 100 was taken from a population. A 94% confidence interval to estimate the mean of the population was co

Firlakuza [10]

Answer:

Step-by-step explanation:

1) The z value was determined using a normal distribution table. From the normal distribution table, the corresponding z value for a 94% confidence interval is 1.88

The correct option is D

2) if 70% of all internet users experience e-mail fraud. It means that probability of success, p

p = 70/100 = 0.7

q = 1 - p = 1 - 0.7 = 0.3

n = number of selected users = 50

Mean, u = np = 50×0.7 = 35

Standard deviation, u = √npq = √50×0.7×0.3 = 3.24

x = number of internet users

The formula for normal distribution is expressed as

z = (x - u)/s

We want to determine the probability that no more than 25 were victims of e-mail fraud. It is expressed as

P(x lesser than or equal to 25)

The z value will be

z = (25- 35)/3.24 = - 10/3.24 = -3.09

Looking at the normal distribution table, the corresponding z score is 0.001

P(x lesser than or equal to 25) = 0.001

7 0

4 years ago