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Misha Larkins [42]
2 years ago
15

For every 15 minutes of driving you've drove 600 miles what is the unit rate

Mathematics
1 answer:
ElenaW [278]2 years ago
4 0

Answer:

Step-by-step explanation:

40 miles per minute

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A customer member owe 16.50 and pays $20 in cash the change due is 3.50 provide the amount owe using the smallest number of bill
Daniel [21]

Answer:

4

Step-by-step explanation:

2 plus 6 is 8, 8 divided by 2 is 4

7 0
3 years ago
Read 2 more answers
In a recent poll, 778 adults were asked to identify their favorite seat when they fly, and 492 of them chose a window seat. Use
seropon [69]

Answer:

Null hypothesis:p \leq 0.5  

Alternative hypothesis:p > 0.5  

z=\frac{\hat p -p_o}{\sqrt{\frac{p_o (1-p_o)}{n}}} (1)  

p_v =P(Z>7.36)=9.19x10^{-14}  

Since the p value obtained was a very low value and using the significance level given \alpha=0.01 we have p_v so we can conclude that we have enough evidence to reject the null hypothesis, and we can said that at 1% of significance the proportion of adults prefer window seats when they fly is significantly higher than 0.5 .  

Step-by-step explanation:

1) Data given and notation

n=778 represent the random sample taken

X=492 represent the people that chose a window seat.

\hat p=\frac{492}{778}=0.632 estimated proportion of people that chose a window seat.

p_o=0.5 is the value that we want to test

\alpha=0.01 represent the significance level

Confidence=99% or 0.99

z would represent the statistic (variable of interest)

p_v represent the p value (variable of interest)  

2) Concepts and formulas to use  

We need to conduct a hypothesis in order to test the claim that the majority of adults prefer window seats when they fly:  

Null hypothesis:p \leq 0.5  

Alternative hypothesis:p > 0.5  

When we conduct a proportion test we need to use the z statisitc, and the is given by:  

z=\frac{\hat p -p_o}{\sqrt{\frac{p_o (1-p_o)}{n}}} (1)  

The One-Sample Proportion Test is used to assess whether a population proportion \hat p is significantly different from a hypothesized value p_o.

3) Calculate the statistic  

Since we have all the info requires we can replace in formula (1) like this:  

z=\frac{0.632 -0.5}{\sqrt{\frac{0.5(1-0.5)}{778}}}=7.36  

4) Statistical decision  

It's important to refresh the p value method or p value approach . "This method is about determining "likely" or "unlikely" by determining the probability assuming the null hypothesis were true of observing a more extreme test statistic in the direction of the alternative hypothesis than the one observed". Or in other words is just a method to have an statistical decision to fail to reject or reject the null hypothesis.  

The significance level provided \alpha=0.01. The next step would be calculate the p value for this test.  

Since is a right tailed test the p value would be:  

p_v =P(Z>7.36)=9.19x10^{-14}  

5) Conclusion

Since the p value obtained was a very low value and using the significance level given \alpha=0.01 we have p_v so we can conclude that we have enough evidence to reject the null hypothesis, and we can said that at 1% of significance the proportion of adults prefer window seats when they fly is significantly higher than 0.5 .  

6 0
3 years ago
Suppose figure A underwent a dilation to produce figure B. Are figure A and figure B similar?
TEA [102]

Answer:

<em>Yes, because even though their side lengths are different, their internal angles are the same.</em>

<em />

Step-by-step explanation:

4 0
3 years ago
The measure of the​ angle's supplement is 40​° more than three times that of its complement. find the measure of the angle descr
Lemur [1.5K]
Angle is x. sup - adds up to 180. comp adds up to 90

180-x = 3(90-x)+40
180-x = 270-3x+40
180-x = 310-3x
180+2x = 310
2x = 130
x=65
8 0
3 years ago
If anyone knows how to add together a gpa please do!!! <br><br><br> Add German 100%
kolezko [41]
I believe it’d be a 3.5
6 0
2 years ago
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