Answer:
x = 27°, ∠JLK = 55°
Step-by-step explanation:
From the diagram in the question above,
The exterior angle of a triangle is equal to the sum of the two opposite side
3x+13 = 39+(2x+1)
3x+13 = 40+2x
collect like terms and solve for x
3x-2x = 40-13
x = 27°.
∠JKL = 2x+1
Substitute the value of x
∠JKL = 2(27)+1
∠JKL = 54+1
∠JKL = 55°
3(x + 2) > x
3x + 6 > x
3x - 3x + 6 > x - 3x
6 > -2x
6/-2 < -2x/-2
-3< x
(When dividing by a negative, reverse the direction of the inequality side, reverse it EVERY time you divide by a negative)
ANSWER: -3 < x
Go up on the graph (y axis) and you need to go down 3 on the y axis and go to the right one and repeat. let me know if you want me to draw it out!
