The answe would be 300 because, the perimeter of the windows is 12, then you have to multiply 25 to 12 then bam you get 300, yay!
Answer:
Step-by-step explanation:
1. Null hypothesis: u <= 0.784
Alternative hypothesis: u > 0.784
2. Find the test statistics: z using the one sample proportion test. First we have to find the standard deviation
Using the formula
sd = √[{P (1-P)}/n]
Where P = 0.84 and n = 750
sd =√[{0.84( 1- 0.84)/750]}
sd=√(0.84 (0.16) /750)
SD =√(0.1344/750)
sd = √0.0001792
sd = 0.013
Then using this we can find z
z = (p - P) / sd
z = (0.84-0.784) / 0.013
z =(0.056/0.013)
z = 4.3077
3. Find the p value and use it to make conclusions...
The p value at 0.02 level of significance for a one tailed test with 4.3077 as z score and using a p value calculator is 0.000008254.
4. Conclusions: the results is significant at 0.02 level of significance suck that we can conclude that its on-time arrival rate is now higher than 78.4%.
Answer:
<u>0.12, 6/50</u> are the answers.
Step-by-step explanation:
1/5 = 0.2
1.2/10 = 0.12
0.12 = 6/50
Have a nice day!
Mean: 74
(72+72+73+75+78) divided by 5
median: 73
(line all the numbers up in numerical order then cross out one from each side and repeat process until in the middle)
Alright, so we start off my subtracting 4a from both sides, separating the x and getting 10-4a=2x. Next, we divide both sides by 2, getting that 5-2a=X
