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3 years ago

Simplify the following expressions by combining like terms. Then, tell if the expressions are equivalent.

Mathematics

1 answer:

dezoksy [38]3 years ago

6 0

Answer:

2+4r. Expressions are equivalent.

Step-by-step explanation:

3r + 10 + r -8

Multiply r and 3

Multiply r and 1

The r just gets copied along.

The answer is r

r

3*r evaluates to 3r

3*r+10 evaluates to 3r+10

3r + r = 4r

The answer is 4r+10

3*r+10+r evaluates to 4r+10

10 - 8 = 2

The answer is 2+4r

3*r+10+r-8 evaluates to 2+4r

The final answer is

2+4r

8 + 2(2r) - 6

Multiply r and 2

Multiply r and 1

The r just gets copied along.

The answer is r

r

2*r evaluates to 2r

Multiply 2 and 2r

Multiply 1 and r

The r just gets copied along.

r

2*(2*r) evaluates to 4r

8+2*(2*r) evaluates to 8+4r

8 - 6 = 2

The answer is 2+4r

8+2*(2*r)-6 evaluates to 2+4r

The final answer is

2+4r

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A test consists of 10 true or false questions. To pass the test a student must answer at least eight questions correctly. If the

forsale [732]

<h3>The probability of student passing the quiz with at least 50% of the questions correct is 0.05457.</h3>

Step-by-step explanation:

Here, the total number of T/F question = 10

The minimum answers needed correctly answered = 8

So, student needs to answer at least 8 questions correctly.

Here, the possibility of answering a question correctly = $(\frac{1}{2})$ = p = 0.5

Also, the possibility of answering a question wrong = $(\frac{1}{2})$ = q = 0.5

Now, to pass he needs to answer 8 or more ( 8 , 9 or 10) answers correctly.

P(answering 8 correct answer) = $^{10}C_8(p)^8(q)^2 = ^{10}C_8(0.5)^8(0.5)^2 = 0.0439$

P(answering 9 correct answer) = $^{10}C_9(p)^9(q)^1 = ^{10}C_9(0.5)^9(0.5)^1 = 0.0097$

P(answering 10 correct answer) = $^{10}C_{10}(p)^{10}(q)^0 = ^{10}C_{10}(0.5)^{10}(0.5)^0 = 0.00097$

So, the total Probability = P(8) + P(9) + P(10)

= (0.0439) + (0.0097) + (0.00097)

= 0.05457

Hence, the probability that the student passes the quiz with at least 8 of the questions correct is 0.05457.

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3 years ago

A. A mother dolphin is 150.25 meters below sea level. Her calf is 45 meters below sea level.

soldi70 [24.7K]

Answer:

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Step-by-step explanation:

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Rudik [331]

The whole numbers add up to 100. So now we are left with 1/2 or 0.5, 3/5 or .60, and 1/8 or .125. Those add up to 1.225 so the amount of sand in pounds in the wheelbarrow is 101.225. Hope I helped! If you have any questions just leave a comment.

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What is the best classification for -4

Brrunno [24]

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(x + 2) is raised to the fifth power. The third term of the expansion is:

WITCHER [35]

(x+2)^5
n = 3
r = 5
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3 years ago