I think the group 2 survey is likely to be biased towards people who are not too keen on zoos since all the values are small.
From group 1 and 3 the mean number of visits are
(4 + 10 + 6 + 3 + 8 + 7 + 9 + 3 + 4 + 7) / 10
= 61/10
mean = 6
Sorry I know the last part only
correct version is Ei Whitney whom was born December 8 1765
the rest got cut off
Answer: Small box: $13; Large box: $16
Step-by-step explanation:
Answer:
Step-by-step explanation:
The answer is A. 16+10+20= 46
Answer:
3200 people
Step-by-step explanation:
p = The frequency of the dominant gene
q = The frequency of the recessive gene

p+q = 1
⇒p = 1-q
⇒p = 1-0.2
⇒p = 0.8
Hardy-Weinberg formula
p² + 2pq + q² = 1
Now for heterozygous trait
2pq = 2×0.8×0.2 = 0.32
Multiplying with the population
0.32×10000 = 3200
∴ 3200 people would be expected to be heterozygous for this trait.