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Naya [18.7K]
3 years ago
8

Which expressions are equivalent to 2^−4·2^2?

Mathematics
1 answer:
Ede4ka [16]3 years ago
5 0

Answer: the answer is 6)

Step-by-step explanation:

Because 2x^{-4} . 2x^{2} = 2x^{-4+2} = 2x^{-2}

I hope it right

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Someone please help me, this test determines if I pass or not.
Butoxors [25]

Answer:

Your answer is C :)

4 0
2 years ago
50 POINTS + BRAINLIEST
Vedmedyk [2.9K]
X + 2y = 6
2y = -x + 6
  y = -1/2 x + 3 so slope = -1/2

parallel lines  has same slope = -1/2
perpendicular lines slope is opposite and reciprocal so slope = 2  
if slope not equal either -1/2 or 2 then neither.

y = -1/2 x - 5 ....m= - 1/2....  parallel

-2x + y = -4
          y = 2x - 4...m = 2 ....perpendicular

-x + 2y = 2
2y = x + 2
y = 1/2 x + 1 ...m = 1/2 ...neither

x + 2y = -2
2y = -x - 2
 y = -1/2 x - 1 ...m = -1/2 .....parallel

hope it helps
3 0
3 years ago
Read 2 more answers
Numbers like 10,100,1000, and so on are called blank
Evgen [1.6K]
Multiples of 10.

Is that what you are asking?
6 0
3 years ago
Evaluate the expression, if possible: √ 64
astraxan [27]

The square root of a number is the smallest (positive) number possible that when multiplied by it self equals the number in the square root.

The square root of 64 is 8 ( 8 x 8 = 64).

The answer is B.

7 0
3 years ago
Solve (1/81)^x*1/243=(1/9)^−3−1 by rewriting each side with a common base.
elena55 [62]

Answer:

x=(243)log_{\frac{1}{81}}[(\frac{1}{81})-1]

Step-by-step explanation:

you have the following formula:

(\frac{1}{81})^{\frac{x}{243}}=(\frac{1}{9})^{-3}-1

To solve this equation you use the following properties:

log_aa^x=x

Thne, by using this propwerty in the equation (1) you obtain for x

log_{(\frac{1}{81})}(\frac{1}{81})^{\frac{x}{243}}=log_{\frac{1}{81}}[(\frac{1}{81})-1]\\\\\frac{x}{243}=log_{\frac{1}{81}}[(\frac{1}{81})-1]\\\\x=(243)log_{\frac{1}{81}}[(\frac{1}{81})-1]

8 0
3 years ago
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