All categories

3 years ago

What are the best estimate for the amount of lemonade needed to serve six people

Mathematics

2 answers:

Romashka-Z-Leto [24]3 years ago

6 0

Maybe six cups ? i’m not sure

frosja888 [35]3 years ago

6 0

It is probably 6 pints.
Hope it helped.

You might be interested in

Gabriella was offered a job after college earning a salary of $50,000. She will get a

inn [45]

Answer:the 3 firts and the last one

Step-by-step explanation:

I just did it

7 0

3 years ago

PLEASE HELP PLEASE WILL MARK BRAINLY

Shtirlitz [24]

Answer:

Every 18 miles he uses 3 gallons

divide this:

18 ÷ 3 = 6 miles per gallon

30 miles = 30 ÷ 6 = 5 gallons

7 gallons = 7 x 6 = 42 miles

48 miles = 48 ÷ 6 = 8 gallons

10 gallons = 10 x 6 = 60 miles

Hope this helps :D

8 0

3 years ago

Read 2 more answers

What do physical changes do?

frutty [35]

Affect the size, shape, or phase of a substance.

3 0

4 years ago

Read 2 more answers

The heights of the elevators can be modeled by the linear functions. At times t=0. Elevator A is 16 feet above ground floor and

polet [3.4K]

The answer is second one which is B

3 0

3 years ago

Before the pandemic cancelled sports, a baseball team played home games in a stadium that holds up to 50,000 spectators. When ti

spayn [35]

Answer:

(a) $D(x)=-2,500x+60,000$

(b) $R(x)=60,000x-2500x^2$

(d)Optimal ticket price: $12

Maximum Revenue:$360,000

Step-by-step explanation:

The stadium holds up to 50,000 spectators.

When ticket prices were set at $12, the average attendance was 30,000.

When the ticket prices were on sale for $10, the average attendance was 35,000.

(a)The number of people that will buy tickets when they are priced at x dollars per ticket = D(x)

Since D(x) is a linear function of the form y=mx+b, we first find the slope using the points (12,30000) and (10,35000).

$\text{Slope, m}=\dfrac{30000-35000}{12-10}=-2500$

Therefore, we have:

$y=-2500x+b$

At point (12,30000)

$30000=-2500(12)+b\\b=30000+30000\\b=60000$

Therefore:

$D(x)=-2,500x+60,000$

(b)Revenue

$R(x)=x \cdot D(x) \implies R(x)=x(-2,500x+60,000)\\\\R(x)=60,000x-2500x^2$

(c)To find the critical values for R(x), we take the derivative and solve by setting it equal to zero.

$R(x)=60,000x-2500x^2\\R'(x)=60,000-5,000x\\60,000-5,000x=0\\60,000=5,000x\\x=12$

The critical value of R(x) is x=12.

(d)If the possible range of ticket prices (in dollars) is given by the interval [1,24]

Using the closed interval method, we evaluate R(x) at x=1, 12 and 24.

$R(x)=60,000x-2500x^2\\R(1)=60,000(1)-2500(1)^2=\$57,500\\R(12)=60,000(12)-2500(12)^2=\$360,000\\R(24)=60,000(24)-2500(24)^2=\$0$

Therefore:

Optimal ticket price:$12
Maximum Revenue:$360,000

3 0

3 years ago