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2 years ago

Does the equations y = 4x + 1 represent a proportional relationship?

Mathematics

1 answer:

My name is Ann [436]2 years ago

4 0

Answer:

Proportional quantities can be described by the equation y = kx, where k is a constant ratio.

Step-by-step explanation:

So, yes it does.

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How many years would it take to make $500 interest on a 12000 investment at 3% per year

padilas [110]

Answer:

$t=1.4\ years$

Step-by-step explanation:

we know that

The simple interest formula is equal to

$I=P(rt)$

where

I is the Final Interest Value

P is the Principal amount of money to be invested

r is the rate of interest

t is Number of Time Periods

in this problem we have

$t=?\\ P=\$12,000\\ I=\$500\\r=3\%=3/100=0.03$

substitute in the formula above

$500=12,000(0.03t)$

solve for t

$500=360t$

$t=500/360$

$t=1.4\ years$

7 0

3 years ago

Please help me! Question is on image below. Yo peeps Baby yoda is so cute!

Vedmedyk [2.9K]

Answer:

c = 26 cm

Step-by-step explanation:

using the Pythagorean theorem:

10² + 24² = c²

c² = 100 + 576 = 676

c = 26 cm

7 0

3 years ago

What is the value of x^2 divided by y^4 when x=8 and y=2

7nadin3 [17]

Answer:

Step-by-step explanation:

64/16=4

7 0

2 years ago

I need help figuring out how to factor <img src="https://tex.z-dn.net/?f=3%20%7Bx%7D%5E%7B2%7D%20-%2011x%20-%204" id="TexFor

Norma-Jean [14]

Answer:

Step-by-step explanation:

7 0

3 years ago

State the equation of the line that is perpendicular to 4x-3y=10 through the point (-2,4)

Lynna [10]

The equation of the line that is perpendicular to 4x - 3y = 10 through the point (-2,4) is $y-4=\frac{-3}{4}(x+2)$

Solution:

Given, line equation is 4x – 3y = 10

We have to find a line that is perpendicular to 4x – 3y = 10 and passing through (-2, 4)

Now, let us find the slope of the given line,

$\text { Slope of a line }=\frac{-\mathrm{x} \text { coefficient }}{\mathrm{y} \text { coefficient }}=\frac{-4}{-3}=\frac{4}{3}$

We know that, slope of a line $\times$ slope of perpendicular line = -1

$\begin{array}{l}{\text { Then, } \frac{4}{3} \times \text { slope of perpendicular line }=-1} \\\\ {\rightarrow \text { slope of perpendicular line }=-1 \times \frac{3}{4}=-\frac{3}{4}}\end{array}$

Now, slope of our required line = $\frac{-3}{4}$ and it passes through (-2, 4)

The point slope form is given as:

$\begin{array}{l}{y-y_{1}=m\left(x-x_{1}\right) \text { where } m \text { is slope and }\left(x_{1}, y_{1}\right) \text { is point on the line. }} \\\\ {\text { Here in our problem, } m=-\frac{3}{4}, \text { and }\left(x_{1}, y_{1}\right)=(-2,4)} \\\\ {\text { Then, line equation } \rightarrow y-4=-\frac{3}{4}(x-(-2))}\end{array}$

$y-4=\frac{-3}{4}(x+2)$

Hence the equation of line is found out

6 0

2 years ago