Hi there!
Below is the fraction we are working with:
To simplify this fraction down to its lowest form, we see what number(s) can go into the numerator and the denominator evenly. We can start off with the number 2. 2 goes evenly into each number, can't it? :)
So, we can cut down to 
.
is already in it's simplest form. Now, we can see if they're equivalent. If not, we have to start all over.
Since equals 83.3, we have to make sure does, too.
Just divide the numerator by the denominator to see what you have.
5 ÷ 6 = 83.3 with a repeating decimal, so they're equivalent!
Hope this helps!
If you need anything else, don't just sit there - Let me know! :D
Answer:
Probability ball: white - P(W)P(W);
Probability ball: even - P(E)P(E);
Probability ball: white and even - P(W&E).
Probability ball picked being white or even: P(WorE)=P(W)+P(E)-P(W&E).
(1) The probability that the ball will both be white and have an even number painted on it is 0 --> P(W&E)=0 (no white ball with even number) --> P(WorE)=P(W)+P(E)−0P(WorE)=P(W)+P(E)−0. Not sufficient
(2) The probability that the ball will be white minus the probability that the ball will have an even number painted on it is 0.2 --> P(W)−P(E)=0.2P(W)−P(E)=0.2, multiple values are possible for P(W)P(W) and P(E)P(E) (0.6 and 0.4 OR 0.4 and 0.2). Can not determine P(WorE)P(WorE).
(1)+(2) P(W&E)=0 and P(W)−P(E)=0.2P(W)−P(E)=0.2 --> P(WorE)=2P(E)+0.2P(WorE)=2P(E)+0.2 --> multiple answers are possible, for instance: if P(E)=0.4P(E)=0.4 (10 even balls) then P(WorE)=1P(WorE)=1 BUT if P(E)=0.2P(E)=0.2 (5 even balls) then P(WorE)=0.6P(WorE)=0.6. Not sufficient.
Answer: E.
Answer:x= 7, 3
Step-by-step explanation:
Answer:
$3.07
Step-by-step explanation:
22.2/6=3.7
hope this helps!
One is Iraq! :) (Hope this helps!)
