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Ket [755]
3 years ago
8

Shirley earned $12 on Monday, She spent $7 on Tuesday and $3 on Wednesday. How much did she have left to spend on Thursday?

Mathematics
1 answer:
umka21 [38]3 years ago
4 0

Answer:2$

Step-by-step explanation:12-7-3

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Evaluate the following division: (3b-6a)÷(30a-15b)​
shutvik [7]

Evaluate the following division: (3b-6a)÷(30a-15b) is <u>-</u><u>1</u><u>/</u><u>5</u><u>.</u>

<h2><u>INTRODUCTION</u></h2>

~ Algebraic Forms and their Elements

Algebraic form is a mathematical form whose presentation involves symbols or letters to represent unknown numbers.

Elements of Algebra:

1. Variables, Constants and Coefficients

Pay attention to the algebraic form 3x + 2y + 3

From the algebraic form above, x and y are variables (variables), while the number 3 is a constant. A variable is a substitute symbol for a number whose value is not clearly known. While constants are terms of an algebraic form in the form of numbers and do not contain variables.

And what is meant by the coefficient is the constant factor of a term in algebraic form. The coefficient on the 3x term is 3, on the 2y term it is 2.

2. Terms and Factors

» The term is part of the algebraic form which is limited by the operation of addition (+) or difference (-). The term one is an algebraic form that is not connected by the operation of addition or difference.

Example: 2x, 2a², -4xy, . . .

» Term two is an algebraic form that is connected by an operation of sum or difference.

Example: 2x + 3, a² - 4, 3x² - 4x, . . .

» Similar terms in algebraic form are terms that have the same variable and the same power.

Example:

2a is similar to 3a, 4a, etc.

» Factors are part of the algebraic form that is restricted to multiplication operations.

Example: 5n = 5 × n, 5 and n are factors of 4n, respectively.

Calculation Operations on Algebraic Forms

1. Addition and subtraction of algebraic forms can only be done on similar terms.

2. Multiplication and division of algebraic forms.

Multiply two terms by constants or variables.

Example:

3 (4y + 5)

= (3 × 4y) + (3 × 5)

= 12y + 15

Division of two terms with a variable or constant, for example:

(8y+4)/2 = 8y/2 + 4/2 = 4y + 2

<h2><u>DISCUSSION</u></h2>

(3b-6a)÷(30a-15b)

= (-6a + 3b) ÷ (-5(-6a+3b))

= (-6a+3b)/(-5(-6a+3b))

= -1/5

<h3>Conclusion:</h3>

So, Evaluate the following division: (3b-6a)÷(30a-15b) is -1/5.

<h3>Learn More:</h3>

(mampir ke indo:v)

  1. Algebraic subtraction material: https://brainly.co.id/task/35216852
  2. Algebraic arithmetic operations: https://brainly.co.id/task/26250852
  3. The equation of the value of x in algebraic form: https://brainly.co.id/task/42124780

_____________

<h3>Answer Details:</h3>

Class: 7 Middle School

Subject: Math

Material: Chapter 2.1 -Operations of Algebraic Forms

Categorization Code: 7.2.2.1

Keywords: Simple form of algebra

7 0
2 years ago
Who else hates online learning
adelina 88 [10]

Answer:

meee

Step-by-step explanation:

8 0
4 years ago
Read 2 more answers
Please help me with math please
goldfiish [28.3K]

Answer:

no mode

The median and mode are 12

Step-by-step explanation:

The mode is the number that appears most often

Since no number repeats there is no mode

The mean is the average

Add up all the numbers

(12+12+12+12+13+13+15)/7 = 89/7 = 12 5/7

The median is the middle number

There are 7 numbers

7/2 = 3.5

The 4th number is the median

The 4th number is 12

The mode is the number that appears most often which is 12

4 0
3 years ago
Given AD=8, AC=12, BC=15. Find the value of x that would make AADE-AACB<br> E<br> B
Bingel [31]

Answer:

DE = 10

Please put the Brainlest

4 0
3 years ago
Kane is trading for a marathon he starts running 3 miles during every training season each week plans to increase the distance o
Contact [7]

Answer:

(11+w)/4

Step-by-step explanation:

Let the first term be 3 miles

If he plans to increase the distance of his run by 1/4 mile, then

common difference = 1/4

To get the distance Kane runs in a training session after w weeks , we will use the nth term of an AP

Tw = a+(w-1)d

Tw = 3 + (w-1)(1/4)

Tw = 3 + 1/4 w - 1/4

Tw = 11/4 + 1/4 w

Tw = (11+w)/4

Hence the distance Kane runs in a training session after w weeks is (11+w)/4 weeks

4 0
3 years ago
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