-3 / 4 + p = 1/2
LCD 4 and 2 = 4
Multiply by LCD = 4
p. (4)- 3/4 .( 4 ) = 1/2.(4)
4 p - 3 = 2
Add 3 to both sides:
4 p - 3 + 3 = 2 + 3
4 p = 5
Divide both sides by 4 :
4p / 4 = 5 /4
p = 5/4
Answer:
B
Step-by-step explanation:
I think the straw can hold about 15000 mm^3.
Solution :
Given data :
The mean length of the steel rod = 29 centimeter (cm)
The standard deviation of a normally distributed lengths of rods = 0.07 centimeter (cm)
a). We are required to find the proportion of rod that have a length of less than 28.9 centimeter (cm).
Therefore, P(x < 28.9) = P(z < (28.9-29) / 0.07)
= P(z < -1.42)
= 0.0778
b). Any rods which is shorter than
cm or longer than
cm that re discarded.
Therefore,
P (x < 24.84 or 25.16 < x) = P( -59.42 < z or -54.85)
= 1.052
Y^2-y^1/x^2-x^1
15-10/1-3
slope = -5/2