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3 years ago

In the rhombus, Angle 1 = 140. What are Angles 2 and 3? The diagram is not to scale.

Mathematics

2 answers:

Alexus [3.1K]3 years ago

8 0

Answer:

The correct answer is that Angle 2 will be 140 and Angle 3 will be 40.

Step-by-step explanation:

In a rhombus, angles opposite from one another are equal. So, since Angle 1 is 140, we know Angle 2 is also 140.

We also know consecutive angles must equal 180. This means the angle in-between 1 and 2 is equal to 40. Since Angle 3 is half of that, we know it to be 20.

liubo4ka [24]3 years ago

7 0

Answer:

∠2 = 140° and ∠3 = 20°

Step-by-step explanation:

Only the first two choices make any sense, because the angles in a triangle must sum to 180°.

Only the second choice makes any sense, because ∠2 ≅ ∠1.

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Find the value of f(x) at the given value of x: f(x) = (x -4)(x + 3), x = 3

mario62 [17]

Answer:

-6

Step-by-step explanation:

f(x)= (3- 4)(3+3)

=( -1 )(6)

= -6

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3 years ago

If a right triangle has side lengths of 3 cm and 7 cm, what is the length of the hypotenuse? brainliest will report if answer is

Neko [114]

Answer:

Solution given:

length[a]=3cm

base(b)=7cm

hypotenuse [c]=?

we have

by using Pythagoras law

a²+b²=c²

3²+7²=c²

c=√58=7.61m

the length of the hypotenuse is 7.61 or 7.6 or8m.

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3 years ago

Mr. Martin’s math test, which is worth 100 points, has 29 problems. Each problem is worth either 5 points or 2 points. Let x be

klio [65]

(x + y = 29)
(y = 29 - x)
(5x + 2(29 - x) = 100)
(5x + 58 - 2x = 100)
(3x = 42)
(x = 14)
(y = 15)
(14 5-point questions and 15 2-point questions)

6 0

3 years ago

Read 2 more answers

Consider a single spin of the spinner.

alex41 [277]

Answer:

"landing on a shaded portion and landing on a 3"

"landing on an unshaded portion and landing on a number less than 2 "

Step-by-step explanation:

Mutually exclusive means the events will have no intersection.

Let's look at your first choice:

"landing on a shaded portion and landing on an even number"

Landing on a shaded portion would be 1 or 4.

Landing on an even number would be 2 or 4.

There is an intersection (they contain a common element), the 4.

These events are not mutually exclusive.

Let's look at your second choice:

"landing on a shaded portion and landing on a number greater than 3"

Landing on a shaded portion would be 1 or 4.

Landing on a number greater than 3 would be just 4.

There is an intersection; they both contain 4.

These events are not mutually exclusive.

Let's look at your third choice:

"landing on a shaded portion and landing on a 3"

Landing on a shaded portion would be 1 or 4.

Landing on 3 would just be 3.

There is no common elements in the lists listed. These events have no intersection.

These events are mutually exclusive.

Let's look at your fourth choice:

"landing on an unshaded portion and landing on an odd number"

Landing on a unshaded portion would be 2 or 3.

Landing on an odd number would be 1 or 3.

There is an intersection; they both have 3 in common.

These events are not mutually exclusive.

Let's look at your fifth choice:

"landing on an unshaded portion and landing on a number less than 2 "

Landing on an unshaded portion would 2 or 3.

Landing on a number less than 2 would be 1.

There is no intersection.

These events are mutually exclusive.

6 0

3 years ago

Read 2 more answers

Find the range of the function.

borishaifa [10]

Answer:

y >= 8

Step-by-step explanation:

This equation is written in vertex notation, so we know the vertex is (-5,8). The parabola opens upward because the coefficient of the squared term is positive. Therefore, the vertex is the minimum, meaning all y values will be greater than (or equal to) the y-coordinate of the vertex (which is 8). When we convert this into a mathematical inequality, we get y>=8.

7 0

3 years ago

Read 2 more answers