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iogann1982 [59]
3 years ago
12

The expected activity time in PERT analysis is calculated as: the weighted average of a, m, and b, with m weighted 4 times as he

avily as a and b. the sum of the optimistic, pessimistic, and most likely times, divided by six. the simple average of the optimistic, pessimistic, and most likely times. the sum of the activity variances, divided by six. the sum of the optimistic, pessimistic, and most likely times.
Mathematics
1 answer:
maria [59]3 years ago
3 0

Answer:

\text{the weighted average of a, m, and b, with m weighted 4 times as heavily as a and b.}

Step-by-step explanation:

\text{The expected activity time in PERT analysis is calculated as:}

\mathbf{\dfrac{a+4m + b}{6}}

where;

\text{a = optimistic duration; }

\text{m = most likely duration and;}

\text{ b = pessimistic duration     from the above formula.}

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Where is EF to the nearest tenth??
Katena32 [7]

Answer:

37.7

Step-by-step explanation:

EF and ED define the Tangent of D

Tan(37) = side opposite D / side adjacent to D

Opposite means a line (FE) that is not connected to the angle. It is never the longest line (hypotenuse) in a Right Triangle

Adjacent means the leg that is connected to the angle, but is not the hypotenuse.

Tan(D) = opposite over adjacent

Opposite = x

Adjacent = 50

Tan(37) = 0.7536 rounded to 4 places, but I've kept the exact value in my calculator.

0.7536 = x / 50     Multiply both sides by 50

0.7536*50 = x

x = 37.6777

The nearest 1/10 is 37.7

6 0
3 years ago
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viktelen [127]

Answer:

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Step-by-step explanation:

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3 years ago
Help with algebra problem
dem82 [27]

Answer:

Yes

Step-by-step explanation:

To find the answer, you just have to plug the (x,y) values into the equation to see if it is true.

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3 > -30 -12

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3 years ago
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4 0
3 years ago
three friends are in the same algebra class. Their scores on a recent test are three consecutive odd intergers whose sum is 279.
jasenka [17]
X= 1st integer
x+2= 2nd integer
x+4= 3rd integer

Add the integers together

x + (x + 2) + (x + 4)= 279
combine like terms
3x + 6= 279
subtract 6 from both sides
3x= 273
divide both sides by 3
x= 91 first integer

Substitute x=91 to find 2nd & 3rd integers

2nd Integer
=x+2
=91+2
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3rd Integer
=x+4
=91+4
=95

ANSWER: The three test scores are 91, 93 and 95.

Hope this helps! :)
7 0
3 years ago
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