9514 1404 393
Answer:
7.056 × 10^31
Step-by-step explanation:
The applicable rule of exponents is ...
(10^a)(10^b) = 10^(a+b)
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As you know, the commutative and associative properties of multiplication let you rearrange the order of the product to any convenient form. Here it is convenient to group the mantissas together and the powers of 10 together.
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<em>Additional comments</em>
This is a product your scientific or graphing calculator can produce for you. Likely it will display the result in scientific notation because it won't have enough display digits to show you the product any other way. For smaller numbers, you can set the display mode to give you scientific notation.
If you choose to use a spreadsheet to perform this calculation, the numbers would be entered as 1.2e19 and 5.88e12. The result will be something like 7.056e31. You may have to format the display to show 3 decimal places.
I believe the answer is 64
First break it off into 2 rectangles on is 4 width and 10 length other is 8 length and 10 width. Then multiple to find area 10•4=40 8•3=24 then add 40+24= 64
Answer:
a. domain: {0, 2, 4}, range: {2, 6, 10}
Step-by-step explanation:
The given diagram depicts a function.
Let us define function:
A function is a mapping of inputs to output.
The left ones are the input of the function while the right side values are the output of the function.
The domain of the function is the set of values that are given as input to the function while the outputs are called range.
so, in the given question
The domain is: {0,2,4} and the range is: {2,6,10}
So, Option A is correct ..
Answer:
178 ERASERS
Step-by-step explanation:
YOU NEED TO START BACKWARDS. HE BOUGHT 76 ERASERS AND HE HAS 193, SO WHATEVER HE HAD AT THE END OF TUESDAY+76 IS HOW MUCH HE HAS ON WEDNESDAY. 193-76=117. ON TUESDAY, HE STARTED WITH ERASERS AT END OF TUESDAY+39 ERASERS. 117+39=156. ON MONDAY, HE STARTED WITH END OF MONDAY+22 ERASERS. 156+22=178
Answer:
If Z is a complex number:
Z = a + b*i
where a and b are real numbers, and i is an imaginary number.
Then "a" is the real part.
"b*i" is the imaginary part.
The conjugate of Z is:
Zc = a - b*i
So the sign of the imaginary part changes.
Then:
Sum:
Z + Zc = (a + bi) + (a - bi) = 2*a + 0 = 2*a
and remember that a is a real number, then 2*a is also a real numer.
The correct answer is "A real number".
Difference:
Z - Zc = (a + bi) - (a - bi) = 2b*i
and this is a pure imaginary number, so here the correct answer is: "a pure imaginary number"
