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nirvana33 [79]
3 years ago
7

Which of the following statement best describes the effect of replacing the graph of f(x) with the graph of f(x) - 3?

Mathematics
2 answers:
ladessa [460]3 years ago
6 0
B  because all the subtraction is done last
Dafna11 [192]3 years ago
3 0
To move a graph up c units, add c to the whole function

so basicaly what you did is you subtraced 3 from the whole function

the whole graph shifts 3 units down

B is answer
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Solve 5x – 2 = 13 show your work
aniked [119]

Answer:

x = 3

General Formulas and Concepts:

<u>Pre-Algebra</u>

Order of Operations: BPEMDAS

  1. Brackets
  2. Parenthesis
  3. Exponents
  4. Multiplication
  5. Division
  6. Addition
  7. Subtraction
  • Left to Right

Equality Properties

Step-by-step explanation:

<u>Step 1: Define</u>

5x - 2 = 13

<u>Step 2: Solve for </u><em><u>x</u></em>

  1. Add 2 on both sides:                    5x = 15
  2. Divide 5 on both sides:                 x = 3
6 0
2 years ago
Help me please thank you
LuckyWell [14K]

Answer:

$13.70

Step-by-step explanation:

$59.60 - $4.80 = $54.80

$54.80 / 4 = $13.70

3 0
3 years ago
Read 2 more answers
1/8+1/3 what is the answer?
kow [346]

Answer:

11/24 as a fraction but a decimal 0.4583 ( the three is recurring)

8 0
3 years ago
Read 2 more answers
Calculate the mean given the frequency table
ratelena [41]

Answer:

15.6

Step-by-step explanation:

First, multiply the midpoint of each class by its frequency, as follows:

            Class      midpoint   frequency   midpoint*frequency  

            0-9         4.5             24                4.5*24 = 108

            10-19      14.5            20                14.5*20 = 290

            20-29    24.5           32                24.5*32 = 784

Total                                      76               1182

The mean is computed as the division between the addition of the "midpoint*frequency" column by the addition of "frequency" column.

mean = 1182/76 ≈ 15.6

 

5 0
3 years ago
A cargo grain leaves Chicago at noon travelling west at 120 km/h. At 2 pm, a passenger train leaves Chicago travelling east at 3
AfilCa [17]

Answer:

a) The trains will be 1520 km apart at 2:40 pm for the cargo train and at 4:40 pm for the passenger train.

b) At that time the cargo train has traveled 560.04 km and the passenger train has traveled 960.12 km.

Step-by-step explanation:

a) First, we need to find the distance traveled by the cargo train in the two hours before the passenger train leaves Chicago:

x_{1} = v_{1}t_{1} = 120 km/h*2h = 240 km                    

Now, we can find the time when the trains will be 1520 km apart:

1520 km = (x_{1} + 240 km) + x_{2}      

Where 1 is for the cargo train and 2 is for the passenger train.

1520 km = (v_{1}*t_{1} + 240 km) + v_{2}t_{2}      

Since we need to calculate the time when the trains are 1520 km apart, t₁ = t₂, so:

1520 km = (v_{1}*t + 240 km) + v_{2}t              

t = \frac{1520 km - 240 km}{120 km/h + 360 km/h} = 2.667h

For the cargo train, it will be 1520 km apart from the passenger train at:

t_{1} = 12 pm + 2 h + 40 min = 2:40 pm

And for a passenger train, it will be 1520 km apart from the cargo train at:

t_{2} = 2 pm + 2 h + 40 min = 4:40 pm  

Hence, the trains will be 1520 km apart at 2:40 pm for the cargo train and at 4:40 pm for the passenger train.  

b) The distance traveled by both trains is given by:

x_{1} = v_{1}*t + 240 km = 120 km/h*2.667 h + 240 km = 560.04 km    

x_{2} = v_{2}*t = 360 km/h*2.667 h = 960.12 km    

Therefore, at that time the cargo train has traveled 560.04 km and the passenger train has traveled 960.12 km.

I hope it helps you!        

5 0
2 years ago
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