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Pani-rosa [81]
3 years ago
5

Solve for the value of x

Mathematics
2 answers:
sp2606 [1]3 years ago
8 0
The answer is c, and for a heads up Photomath is a good app to use for math
SSSSS [86.1K]3 years ago
5 0
A = B
3x+20 = 5x-12
Subtract 3x on both sides
20 = 2x-12
Add 12 on both sides
32 = 2x
Divide by 2 on both sides
16 = x

Option c
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I don’t get this please help me
frez [133]

Answer:#1: 1225

#2: 1149

Step-by-step explanation:

Hope this helps! :) ❤❤❤

3 0
3 years ago
You are collecting a sample of 60 data points from a population that you know to follow an exponential distribution. It is not a
11111nata11111 [884]

Answer:

For the exponential distribution:

\mu = \frac{1}{\lambda}

\sigma^2 = \frac{1}{\lambda^2}

We know that the exponential distribution is skewed but the sample mean for this case using a sample size of 60 would be approximately normal, so then we can conclude that if we have a sample size like this one and an exponential distribution we can approximate the sample mean to the noemal distribution and indeed use the Central Limit theorem.

\bar X \sim N(\mu_{\bar X} , \frac{\sigma}{\sqrt{n}})

\mu_{\bar X} = \bar X

\sigma_{\bar X}= \frac{\sigma}{\sqrt{n}}

Step-by-step explanation:

The central limit theorem states that "if we have a population with mean μ and standard deviation σ and take sufficiently large random samples from the population with replacement, then the distribution of the sample means will be approximately normally distributed. This will hold true regardless of whether the source population is normal or skewed, provided the sample size is sufficiently large".

For this case we have a large sample size n =60 >30

The exponential distribution is the probability distribution that describes the time between events in a Poisson process.

For the exponential distribution:

\mu = \frac{1}{\lambda}

\sigma^2 = \frac{1}{\lambda^2}

We know that the exponential distribution is skewed but the sample mean for this case using a sample size of 60 would be approximately normal, so then we can conclude that if we have a sample size like this one and an exponential distribution we can approximate the sample mean to the noemal distribution and indeed use the Central Limit theorem.

\bar X \sim N(\mu_{\bar X} , \frac{\sigma}{\sqrt{n}})

\mu_{\bar X} = \bar X

\sigma_{\bar X}= \frac{\sigma}{\sqrt{n}}

5 0
4 years ago
How tall are you ?<br> no ped.o type stuff, im just bored and wanna know
kobusy [5.1K]

Answer:

interesting question lol, I am 5'7"

5 0
3 years ago
Read 2 more answers
Sofia and her mother decided to start a tomato garden they went to the store and purchase 48 tomato plants Sophia wanted to have
Hunter-Best [27]

Answer:

6 rows

Step-by-step explanation:

Total plants ÷ tomatoes in each row = # of rows.

48÷8=6

6 rows.

5 0
3 years ago
60 over 100 as a decimal
pshichka [43]

Answer:

0.6

Explanation: 60 over 100 would be 60/100, so when converting this into a decimal, the 60 would be in the hundreths place. Therefore, the decimal would be 0.6.

Hope this Helps!

8 0
3 years ago
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