Answer:
Explanation:
#include <iostream>
using namespace std;
int main ()
{
int responses[30],count[6];
int score = 0;
string resp = " ";
for (int i = 0; i < 30; i++)
{
responses[i] = 0;
}
for (int i = 0; i < 6; i++)
{
count[i,1]=0;
count[i,2]=0;
count[i,0]=0;
}
while ((resp != "Y") && (resp != "y"))
{
for (int i = 0; i < 30; i++)
{
while ((score > 5) || (score < 1))
{
cout << "Student " << (i+1)<< " please enter a value (1-5):";
cin >> score;
}
responses[i] = score;
if((score > 5)||(score<1))
{
if(score==1) count[1]++;
if(score==2) count[2]++;
if(score==3) count[3]++;
if(score==4) count[4]++;
if(score==5) count[5]++;
}
score = 0;
}
cout<< "Response Frequency Percentage"<<endl;;
cout<< " 1 "<<count[1]<<" "<<(count[1]/30)<<"%"<<endl;
cout<< " 2 "<<count[2]<<" "<<(count[2]/30)<<"%"<<endl;
cout<< " 3 "<<count[3]<<" "<<(count[3]/30)<<"%"<<endl;
cout<< " 4 "<<count[4]<<" "<<(count[4]/30)<<"%"<<endl;
cout<< " 5 "<<count[5]<<" "<<(count[5]/30)<<"%"<<endl;
cout<< "Do you want to exit? Press Y to exit any other key to continue: ";
cin>> resp;
}
return 0;
}
C is a sentence fragment it does not have a verb
Answer:
it can be hacked
Explanation:
there is always a chance for computer data to be hacked
Answer:
see explaination
Explanation:
I made use of python program to solve this.
text file name with fun.txt.
6 fun. 3 hello 10 <> 2 25 4 wow!
Program code:
import re
file = open('fun.txt','r') #for reading file
strings="" #declaring empty string
for k in file:
strings=strings+k #all character in file is storing in strings variable for do operations
pattern = '\s' #for pattern \s is for space
result = re.split(pattern, strings) #split the string with space
for k in range(len(result)): #loop through the list of string
if(k%2) == 0: #checking for integer to time of string
p=int(result[k])
print(result[k+1] *p) #print times of the string(k+1)
Check attachment for output
