Answer:
Command remembering issues.
Explanation:
The biggest challenge my company will face when working on Linux is remembering issues of the commands. The commands in Linux are a bit difficult to remember as they are complicated bit but practice can solve this issue. "Practice makes a man perfect" this well known saying suggests that practice can make perfect and this well known saying also works with Linux the more practice the employees do the more perfect they get.
Answer:
Option B, Vanishing point
Explanation:
The complete question is
Where do the projection lines converge in a perspective sketch?
A. the ground line
B. the vanishing line
C. the eye point
D. the horizon line
Solution
A point lying on the image of a perspective drawing where the drawings ( two-dimensional perspective projections) of two parallel line meet in three dimensional space is known as Vanishing point
Answer:
prompt("Enter a value for one edge of a cube")
Store user's value into edgeCube
area = 6 * (edgeCube * edgeCube)
volume = edgeCube * edgeCube * edgeCube
print("One side of the cube is: " + edgecube);
print("The area is: " + area)
print("The volume is: " + volume)
Answer:
(d) all of the above
Explanation:
This is because, not only is digital video a core technology for digital television, it also happens to be a core technology for video conferencing and video messaging. This could be seen in its application in messaging apps for private discussion of for holding official meetings between employees in virtual conference.
Answer:
Check the explanation
Explanation:
#define _MULTI_THREADED
#include <pthread.h>
#include <stdio.h>
#include <errno.h>
#define THREADS 2
int i=1,j,k,l;
int argcG;
char *argvG[1000];
void *threadfunc(void *parm)
{
int *num;
num=(int*)parm;
while(1)
{
if(i>=argcG)
break;
if(*num ==1)
if(argvG[i][0]=='a' ||argvG[i][0]=='2'||argvG[i][0]=='i' ||argvG[i][0]=='o' ||argvG[i][0]=='u')
{
printf("%s\n",argvG[i]);
i++;
continue;
}
if(*num ==2)
if(!(argvG[i][0]=='a' ||argvG[i][0]=='2'||argvG[i][0]=='i' ||argvG[i][0]=='o' ||argvG[i][0]=='u'))
{
printf("%s\n",argvG[i]);
i++;
continue;
}
sched_yield();
}
return NULL;
}
int main(int argc, char *argv[])
{
pthread_t threadid[THREADS];
int rc=0;
int loop=0;
int arr[2]={1,2};
argcG=argc;
for(rc=0;rc<argc;rc++)
argvG[rc]=argv[rc];
printf("Creating %d threads\n", THREADS);
for (loop=0; loop<THREADS; ++loop) {
rc =pthread_create(&threadid[loop], NULL, threadfunc,&arr[loop]);
}
for (loop=0; loop<THREADS; ++loop) {
rc = pthread_join(threadid[loop], NULL);
}
printf("Main completed\n");
return 0;
}
The below attached image is a sample output
