Answer:
![A=(72+36\sqrt{3})\ mm^2](https://tex.z-dn.net/?f=A%3D%2872%2B36%5Csqrt%7B3%7D%29%5C%20mm%5E2)
Step-by-step explanation:
see the attached figure with letters to better understand the problem
Let
a ----> the height of rectangle in mm
b ---> the base of rectangle in mm
step 1
Find the base of rectangle
----> by segment addition postulate
substitute
![b=3+3+3+3=12\ mm](https://tex.z-dn.net/?f=b%3D3%2B3%2B3%2B3%3D12%5C%20mm)
step 2
Find the height of rectangle
---> by segment addition postulate
substitute the given values
![a=3+CG+3\\a=6+CG](https://tex.z-dn.net/?f=a%3D3%2BCG%2B3%5C%5Ca%3D6%2BCG)
Find the length sides CG
Applying the Pythagorean Theorem
![BG^2=BC^2+CG^2](https://tex.z-dn.net/?f=BG%5E2%3DBC%5E2%2BCG%5E2)
substitute the given values
![6^2=3^2+CG^2](https://tex.z-dn.net/?f=6%5E2%3D3%5E2%2BCG%5E2)
![CG^2=6^2-3^2](https://tex.z-dn.net/?f=CG%5E2%3D6%5E2-3%5E2)
![CG=\sqrt{27}\ mm](https://tex.z-dn.net/?f=CG%3D%5Csqrt%7B27%7D%5C%20mm)
simplify
![CG=3\sqrt{3}\ mm](https://tex.z-dn.net/?f=CG%3D3%5Csqrt%7B3%7D%5C%20mm)
therefore
![a=(6+3\sqrt{3})\ mm](https://tex.z-dn.net/?f=a%3D%286%2B3%5Csqrt%7B3%7D%29%5C%20mm)
step 3
Find the area of rectangle
![A=ab](https://tex.z-dn.net/?f=A%3Dab)
we have
![a=(6+3\sqrt{3})\ mm](https://tex.z-dn.net/?f=a%3D%286%2B3%5Csqrt%7B3%7D%29%5C%20mm)
![b=12\ mm](https://tex.z-dn.net/?f=b%3D12%5C%20mm)
substitute
![A=(6+3\sqrt{3})(12)=(72+36\sqrt{3})\ mm^2](https://tex.z-dn.net/?f=A%3D%286%2B3%5Csqrt%7B3%7D%29%2812%29%3D%2872%2B36%5Csqrt%7B3%7D%29%5C%20mm%5E2)
6.37864 kilo ... hopefully thats helpful!
Answer:
820
Step-by-step explanation:
100j+40h
100(5)+40(8)
500+320
820!
The result of dividing
![15x^{3}+x^{2}-3x+2](https://tex.z-dn.net/?f=15x%5E%7B3%7D%2Bx%5E%7B2%7D-3x%2B2)
by
![3x+2](https://tex.z-dn.net/?f=3x%2B2)
is
![5 x^{2} -3x+1](https://tex.z-dn.net/?f=5%20x%5E%7B2%7D%20-3x%2B1)
with no remainder. Please check the step by step procedures in the picture attached.
We can conclude that:
The quotient of the division is
![5 x^{2} -3x+1](https://tex.z-dn.net/?f=5%20x%5E%7B2%7D%20-3x%2B1)
The remainder of the division is
![0](https://tex.z-dn.net/?f=0)
The divisor is
![3x+2](https://tex.z-dn.net/?f=3x%2B2)
The dividend is