<em>T</em><em>he</em><em> </em><em>right</em><em> </em><em>answer</em><em> </em><em>is</em><em> </em><em>-</em><em>3</em><em>.</em>
<em>Look</em><em> </em><em>at</em><em> </em><em>the</em><em> </em><em>attached</em><em> </em><em>picture</em><em> </em><em>⤴</em>
<em>Hope</em><em> </em><em>it</em><em> </em><em>will</em><em> </em><em>help</em><em> </em><em>u</em><em>.</em><em>.</em><em>:</em><em>)</em>
Solution
=14
Step-by-step explanation:
<h2>
3x-12=2x+2</h2><h2>
3x-12=2x+23x-2x-12=2</h2><h2>
3x-12=2x+23x-2x-12=2x=12+2</h2><h2>
3x-12=2x+23x-2x-12=2x=12+2x=14</h2>
Answer:
5.625
Step-by-step explanation:
45 ÷ 8 = 5.625
<span>a.
</span>Do you
have sufficient funds to estimate the population mean for the attribute of
interest with a 95% confidence interval 4 units width? Assume that sd= 12
n= {[(Zalpha/2)^2]*[sd]^2}/
se^2
n=
(1.96)^2*(12)^2/ (2)^2
n=
138.297 rounded up to 139
<span>There
is not enough funds for this one
since you’ll need 139 pieces and it costs 10 a piece, you’ll need 1390.</span>
b.
90% confidence interval
n= {[(Zalpha/2)^2]*[sd]^2}/
se^2
n=
(1.645)^2*(12)^2/ (2)^2
n=98
There is enough
funds since 98 pieces for 10 a piece is equal to 980.
28= 1,2,4,7,14,28,
44=1,2,4,11,22,44,
