Answer:
A farmer has enough food to feed 20 animals in his cattle for 6 days. How long would the food last if there were 10 more animals in his cattle? Here the number of animals and the number of days are in inverse proportion. Hence the food will last 4 days.
Answer:
9x^2 - 3x - 2, R -7.
Step-by-step explanation:
x - 5) 9x^3 - 48x^2 + 13x + 3(9x^2 - 3x - 2 <---- Quotient.
9x^3 - 45x^2
- 3x^2 + 13x
-3x^2 + 15x
-2x + 3
-2x + 10
-7 <----- Remainder
we are given
x-intercept is 3
so,
a=3
y-intercept is 2
b=2
now, we can intercept formula of line
now, we can plug
a=3 and b=2
now, we will get rid of denominators
so, we can multiply both sides by 6
we can also write it as
so, option-D..................Answer
Answer:
D. 11.25 students per year
Step-by-step explanation:
