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3 years ago

BRAINLY HELP NEEDED ASAP

Mathematics

1 answer:

forsale [732]3 years ago

7 0

Step-by-step explanation:

increase in Tyler's pay = 16 - 14 = 2

% increase in Tyler's pay = 2/14 × 100 = 14.3%

Increase in Allies' pay = 18 - 16 = 2

% increase in Allies'pay = 2/16 × 100 = 12.5%

hence the right option is:

3).The percent increase Tyler's pay rate is greater than Allies'.

Increase in Martin's pay = 15.00 - 13.50 = 1.50

% increase in Martin's pay = 1.50/13.50 = 11.1%

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viva [34]

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3 years ago

Plz help!! A jar contained 6 red marbles, 10 green marbles, and 8 blue marbles. A marble was selected at random, the color was r

Inessa [10]

Answer:

To calculate the relative frequency, first we need to know what exactly is and how to calculate it.

Relative frequency is the ratio between the absolute frequency (how many repetitions have a specific outcome) and the total outcomes. Also, this type of frequency is used to show the representation that some data have over the whole distribution.

So, in this case, we need to just divide 13, which belongs to red marble's results, to 60 which is the total outcomes, as it's presented:

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Normally, relative frequency is shown as a percentage multiplying this result by 100. Therefore, 22% is the approximate percentage of the relative frequency, which means that 22% is the representation of red marbles outcomes of the whole distribution, or we can say it as a probability: there's 22% of chances when someone extract a marble, it will be red.

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3 years ago

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nignag [31]

Answer:

Both A and B

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For functions you are just trying to make sure all the x's are different.

So let's look at A: The x's there are all different so it is a function

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4 years ago

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nlexa [21]

Answer: 3rd one

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3 years ago

Suppose that a cyclist began a 476

mojhsa [17]

Well, we know the cyclist left the western part going eastwards, at the same time the car left the eastern part going westwards

the distance between them is 476 miles, and they met 8.5hrs later

let's say after 8.5hrs, the cyclist has travelled "d" miles, whilst the car has travelled the slack, or 476-d, in the same 8.5hrs

we know the rate of the car is faster... so if the cyclist rate is say "r", then the car's rate is r+33.2

thus $\bf \begin{array}{lccclll}
&distance&rate&time\\
&-----&-----&-----\\
\textit{eastbound cyclist}&d&r&8.5\\
\textit{westbound car}&476-d&r+33.2&8.5
\end{array}\\\\
-----------------------------\\\\
\begin{cases}
\boxed{d}=8.5r\\\\
476-d=(r+33.2)8.5\\
----------\\
476-\boxed{8.5r}=(r+33.2)8.5
\end{cases}$

solve for "r", to see how fast the cyclist was going

what about the car? well, the car's rate is r + 33.2

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3 years ago

**BRAINLY** HELP NEEDED ASAP

BRAINLY HELP NEEDED ASAP