Answer:
<h2>A. -2</h2>
Step-by-step explanation:
![\det\left[\begin{array}{ccc}a&b\\c&d\end{array}\right] =ad-bc\\\\\det\left[\begin{array}{ccc}3&-5\\1&1\end{array}\right] =(3)(1)+(-5)(1)=3-5=-2](https://tex.z-dn.net/?f=%5Cdet%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7Da%26b%5C%5Cc%26d%5Cend%7Barray%7D%5Cright%5D%20%3Dad-bc%5C%5C%5C%5C%5Cdet%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7D3%26-5%5C%5C1%261%5Cend%7Barray%7D%5Cright%5D%20%3D%283%29%281%29%2B%28-5%29%281%29%3D3-5%3D-2)
A vertical line that the graph of a function approaches but never intersects. The correct option is B.
<h3>When do we get vertical asymptote for a function?</h3>
Suppose that we have the function f(x) such that it is continuous for all input values < a or > a and have got the values of f(x) going to infinity or -ve infinity (from either side of x = a) as x goes near a, and is not defined at x = a, then at that point, there can be constructed a vertical line x = a and it will be called as vertical asymptote for f(x) at x = a
A vertical asymptote can be described as a vertical line that the graph of a function approaches but never intersects.
Hence, the correct option is B.
Learn more about Vertical Asymptotes:
brainly.com/question/2513623
#SPJ1
Answer:
-8
Step-by-step explanation:
First we need to find the slope of CD.
We know C is (-10, -2)
and we know D is (10,6)
If we use the slope formula, we can see the slope is 
We can see point F is at (6,-4)
We can find the equation of this line by using point slope form, and plugging in F as our point.
To find where E, we need to find the y value when x = -4
The slope of the line has to be the same the the equation given to be parallel.
The slope of the line given is... 2/3.
If the line passes through point (1,3) then...
3=2/3(1)+b
b=2 1/3
answer: y=2/3x+2 1/3
