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3 years ago

10

(If anyone can help me tysm)Thomas had a credit of $5 and a debit of $9 posted in his checking account. What is the balance betw

een these two transactions?

1 answer:

deff fn [24]3 years ago

7 0

Answer:

ur doing sca testing lol so its -4 rember debit is negitive credit is positive so 5 - -9= -4

Step-by-step explanation:

5 - (-9) = (-4)

You might be interested in

What are the solutions to x^2-5x+3=0?

Viktor [21]

Answer:

Step-by-step explanation:

You need to use the quadratic equation

x = $\frac{-b +/- \sqrt{b^2 - 4ac} }{2a}$

Givens

a = 1
b = - 5
c = 3

x = $\frac{5 +/- \sqrt{5^2 - 4a*1*3} }{2} \\$

x =( 5 +/- sqrt(25 - 12) ) / 2

x = (5 +/- sqrt(13) )/2

x = (5 + sqrt(13) / 2

x = 4.303 rounded

x = (5 - sqrt(13) ) /2

x = .6972

4 0

3 years ago

Find the value of the integral that converges.<br> ∫^-5_-[infinity] x^-2 dx.

Bingel [31]

Answer:

$\int_{-\infty}^{-5} x^{-2}dx= \frac{1}{5} + \lim_{x\to -\infty} \frac{1}{x} =\frac{1}{5}$

Because the $\lim_{x\to -\infty} \frac{1}{x} =0$

The integral converges to $\frac{1}{5}$

Step-by-step explanation:

For this case we want to find the following integral:

$\int_{-\infty}^{-5} x^{-2}dx$

And we can solve the integral on this way:

$\int_{-\infty}^{-5} x^{-2}dx= \frac{x^{-2+1}}{-2+1} \Big|_{-\infty}^{-5}$

$\int_{-\infty}^{-5} x^{-2}dx= -\frac{1}{x} \Big|_{-\infty}^{-5}$

And if we evaluate the integral using the fundamental theorem of calculus we got:

$\int_{-\infty}^{-5} x^{-2}dx= \frac{1}{5} + \lim_{x\to -\infty} \frac{1}{x} =\frac{1}{5}$

Because the $\lim_{x\to -\infty} \frac{1}{x} =0$

The integral converges to $\frac{1}{5}$

8 0

3 years ago

Forensic specialists can estimate the height of a deceased person from the lengths of the person's bones. These lengths are subs

Lera25 [3.4K]

Answer:

$130.2845\leq h\leq 137.7245$

Step-by-step explanation:

Given an inequality that relates the height h, in centimeters, of an adult female and the length f, in centimeters, of her femur by the equation

$|h - (2.47f + 54.10)| \leq 3.72$

If an adult female measures her femur as 32.25 centimeters, we can determine the possible range of her height by plugging f = 32.25cm into the modelled equation as shown:

$|h - (2.47(32.25) + 54.10)| \leq 3.72\\|h - (79.9045 + 54.10)| \leq 3.72\\|h - (134.0045)| \leq 3.72\\$

If the modulus function is positive then:

$h - 134.0045 \leq 3.72\\h \leq 3.71+134.0045\\h\leq 137.7245$

If the modulus function is negative then:

$-(h - 134.0045) \leq 3.72\\-h+134.0045 \leq 3.72\\-h\leq 3.72-134.0045\\-h\leq -130.2845\\$

multiply through by -1

$-(-h)\geq -(-130.2845)\\h\geq 130.2845\\130.2845\leq h$

combining the resulting inequalities, the estimate of the possible range of heights will be $130.2845\leq h\leq 137.7245$

8 0

3 years ago

The following table shows a portion of a four-year amortization schedule. A 4-year amortization schedule. The loan amount or pri

yKpoI14uk [10]

Answer:

Option c. $ 9,543.97

Explanation:

The row for month 25 shows that after <em>twenty-five payments</em> <u>the balance of the loan is $10,356.03</u>

You are told that the<em> loan amount or principal is $ 19,900</em>.

From those two data, you can calculate <em>how much of the principal has been paid off after </em>25 months, because the amount paid off is equal to the loan less the balance after 25 payments:

Principal paid off = $ 19,900 - $ 10,356.03 = $9,543.97

8 0

3 years ago

Equation álgebra<br> 3x^2 = 12<br> a. +3<br> b. +2<br> C. +3.5<br> d. +1.5

Tom [10]

Answer:

x=-2,2

Step-by-step explanation:

Since this is a quadratic equation, -2 or 2 could be the possible answer

Steps

$3x^2=12$

$\mathrm{Divide\:both\:sides\:by\:}3$

$\frac{3x^2}{3}=\frac{12}{3}$

$\mathrm{Simplify}$

$x^2=4$

$\mathrm{For\:}x^2=f\left(a\right)\mathrm{\:the\:solutions\:are\:}x=\sqrt{f\left(a\right)},\:\:-\sqrt{f\left(a\right)}$

$x=\sqrt{4},\:x=-\sqrt{4}$

Show Steps

$\sqrt{4}=2$

Show Steps

$-\sqrt{4}=-2$

$x=2,\:x=-2$

3 0

3 years ago