Hi anyone know the answer to this? Ill give brainliest immediately!!!! :)

Mathematics

2 answers:

SashulF [63]3 years ago

8 0

It’s the 3rd one :) hope this helps

Wewaii [24]3 years ago

6 0

Option C or y=1/2x+3 is the correct answer.
The line has a slope of 1/2 and a y intercept of (0,3) that matches option c. To graph an equation, Find points: pick simple values of x and find the corresponding values of y. ...
Using the slope and y-intercept: use the concept of “rise over run” and the y-intercept to find points on the graph. ...
Using the x- and y-intercepts: let x=0 and y=0 to find the intercepts of the graph.

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HELP PLEASE ANOTHER QUICK QUESTION !!!!!!

4vir4ik [10]

Third option is Right...... AngleFBY = AngleGBX because they are the only vertically opposite angles mentioned in the options..... the others are not....
Hope this helps!
Don't forget to mark the brainliest if I helped!

5 0

3 years ago

Read 2 more answers

A two digit number is written at random what is the probability that the number will be odd

leonid [27]

Answer:

50%

Step-by-step explanation:

So there are 90 2 digit numbers. There are 45 2 digit odd numbers.

The probability should be 50%

7 0

3 years ago

Am i correct? calculus

Advocard [28]

Check the picture below.

now, the "x" is a constant, the rocket is going up, so "y" is changing and so is the angle, but "x" is always just 15 feet from the observer. That matters because the derivative of a constant is zero.

now, those are the values when the rocket is 30 feet up above.

$\bf tan(\theta )=\cfrac{y}{x}\implies tan(\theta )=\cfrac{y}{15}\implies tan(\theta )=\cfrac{1}{15}\cdot y
\\\\\\
\stackrel{chain~rule}{sec^2(\theta )\cfrac{d\theta }{dt}}=\cfrac{1}{15}\cdot \cfrac{dy}{dt}\implies \cfrac{1}{cos^2(\theta )}\cdot\cfrac{d\theta }{dt}=\cfrac{1}{15}\cdot \cfrac{dy}{dt}
\\\\\\
\boxed{\cfrac{d\theta }{dt}=\cfrac{cos^2(\theta )\frac{dy}{dt}}{15}}\\\\
-------------------------------\\\\
$

$\bf cos(\theta )=\cfrac{adjacent}{hypotenuse}\implies cos(\theta )=\cfrac{15}{15\sqrt{5}}\implies cos(\theta )=\cfrac{1}{\sqrt{5}}\\\\
-------------------------------\\\\
\cfrac{d\theta }{dt}=\cfrac{\left( \frac{1}{\sqrt{5}} \right)^2\cdot 11}{15}\implies \cfrac{d\theta }{dt}=\cfrac{\frac{1}{5}\cdot 11}{15}\implies \cfrac{d\theta }{dt}=\cfrac{\frac{11}{5}}{15}\implies \cfrac{d\theta }{dt}=\cfrac{11}{5}\cdot \cfrac{1}{15}
\\\\\\
\cfrac{d\theta }{dt}=\cfrac{11}{75}$