Solve this problem

Which representation of a transformation on a coordinate grid does not preserve congruence?

Alex17521 [72]

Answer:

B

Step-by-step explanation:

Consider all options:

A. Transformation with the rule

$(x,y)\rightarrow (x,-y)$

is a reflection across the x-axis.

Reflection across the x-axis preserves the congruence.

B. Transformation with the rule

$(x,y)\rightarrow \left(\dfrac{7}{8}x,\dfrac{7}{8}y\right)$

is a dilation with a scale factor of $\frac{7}{8}$ over the origin.

Dilation does not preserve the congruence as you get smaller figure.

C. Transformation with the rule

$(x,y)\rightarrow (x+6,y-4)$

is a translation 6 units to the right and 4 units down.

Translation 6 units to the right and 4 units down preserves the congruence.

D. Transformation with the rule

$(x,y)\rightarrow (y,-x)$

is a clockwise rotation by $90^{\circ}$ angle over the origin.

Clockwise rotation by $90^{\circ}$ angle over the origin preserves the congruence.

3 0

3 years ago

Can you guys please help me my math teacher wants us to get this right and I don’t get it please help me on all of it

Ostrovityanka [42]

#5 is

Let's solve your equation step-by-step.

2

5

x−1=9

Step 1: Add 1 to both sides.

2

5

x−1+1=9+1

2

5

x=10

Step 2: Multiply both sides by 5/2.

(

5

2

)*(

2

5

x)=(

5

2

)*(10)

x=25

Answer:

x=25

7 0

3 years ago

What is 1990 divided by 24?

NNADVOKAT [17]

What is 1990 divided by 24?
1990 divided by 24 is 82 with a remainder of 22 or 83 rounding to the whole number.

4 0

3 years ago

In the 1990s the demand for personal computers in the home went up with household income. For a given community in the 1990s, th

WITCHER [35]

Answer:

a) 0.5198 computers per household

b) 0.01153 computers

Step-by-step explanation:

Given:

number of computers in a home,

q = 0.3458 ln x - 3.045 ; 10,000 ≤ x ≤ 125,000

here x is mean household income

mean income = $30,000

increasing rate, $\frac{dx}{dt}$ = $1,000

Now,

a) computers per household are

since,

mean income of $30,000 lies in the range of 10,000 ≤ x ≤ 125,000

thus,

q = 0.3458 ln(30,000) - 3.045

or

q = 0.5198 computers per household

b) Rate of increase in computers i.e $\frac{dq}{dt}$

$\frac{dq}{dt}$ = $\frac{d(0.3458 ln x - 3.045)}{dt}$

or

$\frac{dq}{dt}=0.3458\times(\frac{1}{x})\frac{dx}{dt} - 0$

on substituting the values, we get

$\frac{dq}{dt}=0.3458\times(\frac{1}{30,000})\times1,000$

or

= 0.01153 computers

6 0

3 years ago

Solve each equation by substitution: y = 6x - 17 y= -4x +23

NISA [10]

Answer:

$y = 6x - 17 \\ y = - 4x + 23 \\ then \\ 6 x - 17 = - 4x + 23 \\ 10x = 40 \\ x = 4 \\ y = 7$

7 0

3 years ago

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