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MissTica
3 years ago
12

Smoke and Sulfuric Acid, It help cool the atmosphere. True or false ?

Biology
2 answers:
GenaCL600 [577]3 years ago
7 0
Often, erupting volcanoes emit sulfur dioxide into the atmosphere. Sulfur dioxide is much more effective than ash particles at cooling the climate. ... The sulfuric acid makes a haze of tiny droplets in the stratosphere that reflects incoming solar radiation, causing cooling of the Earth's surface.
Gelneren [198K]3 years ago
5 0

Answer:  The answer is true

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Place the following statements in the correct order in the blanks below to describe how
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The correct order in the blanks are as follows: <u>C A E F G B</u>

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a. Water enters the phloem through osmosis

e. Pressure from the leaves pushes the water and glucose through the phloem

f. An area of low glucose concentration is reached

g. Glucose is actively transported out of the phloem

b. Water exits the phloem through osmosis

<h3>What is translocation?</h3>

The transport of sugar created during photosynthesis to all other areas of the plant for respiration and the other activities mentioned above is known as translocation.

Utilizing light energy, plants use photosynthesis to convert the inorganic chemicals carbon dioxide and water into glucose. Respiration uses a portion of the glucose created by photosynthesis. The seven biological processes receive energy as a result.

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The info in DNA and mRNA is used to make what kind of molecule?
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3 years ago
If a heterozygous plant with green seeds self-fertilizes, what is the probability that 6 seeds in a single pod of the progeny pl
nalin [4]

Here is the complete question

The seeds in bush bean pods are each the product of an independent fertilization event. Green seed color is dominant to white seed color in bush beans.

If a heterozygous plant with green seeds self-fertilizes, what is the probability that 6 seeds in a single pod of the progeny plant will consist of:

A) 4 green and 2 white seeds?

B) all white seeds?

C) at least 5 white seeds?

Answer:

A) 0.3

B) 0.0002

C) 0.001

Explanation:

Let the allele for Green plant be = P

Let the allele for white plant be =  p

Let the heterozygous plant be Pp, if self fertilization occurs we have:

                   P                    p

P                 PP                 Pp                                                              

                                                           

p                 Pp                 pp                  

From the punnet square above, we have the following  cross;

PP, Pp, Pp, pp

Since P is dominant to p; we have a phenotypic ratio of 3:1 between the dominant phenotype ( PP, Pp, Pp ) and recessive phenotype ( pp )

NOW, the probability for the green plant(i.e PP or Pp) will be: Pr(G)=\frac{3}{4}

the probability for the white plant (pp) will be: Pr (W)= \frac{1}{4}

A)

what is the probability that 6 seeds in a single pod of the progeny plant will consist of 4 green and 2 white seeds?

Pr(4G2W) = (\frac{3}{4})*(\frac{3}{4})*(\frac{3}{4})*(\frac{3}{4})*(\frac{1}{4})*(\frac{1}{4})

The probability includes the use of permutation:

Permutation(P)=\frac{6!}{(4!*2!)} * (\frac{3}{4})*(\frac{3}{4})*(\frac{3}{4})*(\frac{3}{4})*(\frac{1}{4})*(\frac{1}{4})

= 15*(\frac{3}{4})*(\frac{3}{4})*(\frac{3}{4})*(\frac{3}{4})*(\frac{1}{4})*(\frac{1}{4})

= 0.2966

≅ 0.3

B)

What is the probability that 6 seeds in a single pod of the progeny plant will consist of all white seeds?

Since probability for white seed = \frac{1}{4}

The probability that 6 seeds will consist of all white seeds will be = (\frac{1}{4})^6

=  2.44 × 10⁻⁴

= 0.000244

≅ 0.0002

C)

What is the probability that 6 seeds in a single pod of the progeny plant will consist of at least 5 white seeds?

For at least 5 white seeds, the probability will consist of  5 white seeds and 6 white seeds.

For 5 white seeds; we have:

5 White  and 1 Green  Since there are 6 permutations.

The probability For 5 white seeds will therefore be :

Pr(5 seeds)=(\frac{1}{4})^5*(\frac{3}{4})^1 *6

= 7.32 × 10⁻⁴

= 0.000732

For 6 white seeds; we have:

Only one permutation for 6 whites since there will no be any presence of any green seed.

Pr(6seeds)=(\frac{1}{4})^6

= 2.44 × 10⁻⁴

= 0.000244

∴

The total probability for at least 5 white seeds =  0.000732 + 0.000244

= 9.76  × 10⁻⁴

= 0.000976

≅ 0.001

3 0
3 years ago
Bacteria undergo an asexual process of cell splitting called binary fission. This process is genetically similar to?
belka [17]
A). Mitosis is correct :)
7 0
4 years ago
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