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3 years ago

Find the width w of a box with volume V = 120 cm3, l = 3 cm and h = 5 cm.

Mathematics

2 answers:

LenKa [72]3 years ago

8 0

Answer:

Step-by-step explanation:

the volume of a box is L x W x H

so if you take the length x height, you can divide the volume by that to get your width.

hope this helps!! :)

Triss [41]3 years ago

5 0

Answer:

volume = l*b*h

120= 3*b*5

120=15b

15b=120

b=130/15

b=8

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Y''+y'+y=0, y(0)=1, y'(0)=0

mars1129 [50]

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$y=e^{\frac{-t}{2}}\left ( \cos\left ( \frac{\sqrt{3}t}{2} \right )+\frac{1}{\sqrt{3}}\sin \left ( \frac{\sqrt{3}t}{2} \right ) \right )$

Step-by-step explanation:

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We get,

$y=\frac{-1\pm \sqrt{1^2-4}}{2}=\frac{-1\pm \sqrt{3}i}{2}$

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So, equation becomes $y=e^{\frac{-t}{2}}\left ( \cos\left ( \frac{\sqrt{3}t}{2} \right )+c_2\sin \left ( \frac{\sqrt{3}t}{2} \right ) \right )$

On differentiating with respect to t, we get

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Applying condition: y'(0)=0, we get $0=\frac{-1}{2}+\frac{\sqrt{3}}{2}c_2\Rightarrow c_2=\frac{1}{\sqrt{3}}$

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$y=e^{\frac{-t}{2}}\left ( \cos\left ( \frac{\sqrt{3}t}{2} \right )+\frac{1}{\sqrt{3}}\sin \left ( \frac{\sqrt{3}t}{2} \right ) \right )$

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Katena32 [7]

HI
LET ME HELP YOU WITH YOUR QUESTION

1 kg = 1000 grams

Since 1kg = 1000 grams then 65 kg will = 65000 grams
hope it helps

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