V2 + 2v + 1 is the product of which two binomials?

2 answers:

8 0

The answer is (v+1)^2

(side note: when writing exponents use "^" to indicate the following number is an exponent. ex. 3 squared would be 3^2)

juin [17]3 years ago

6 0

(V+1)2 is that right

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What is the distance between (-3,5) (7,5)

Firlakuza [10]

Answer:

10 units

Step-by-step explanation:

use distance formula: d = square root of the difference of the y-values minus the difference of the x-values

d = $\sqrt{(5-5)^2+(7--3)^2}$

d = $\sqrt{(0)^2+(10)^2}$

d = $\sqrt{100}$

d = 10 units

4 0

3 years ago

Read 2 more answers

Consider a game in which a participant pays $2 to roll a die. The participant receives $3 if they roll a 1 (i.E. They go up by a

Sauron [17]

Answer:

The expected monetary value of a single roll is $1.17.

Step-by-step explanation:

The sample space of rolling a die is:

S = {1, 2, 3, 4, 5 and 6}

The probability of rolling any of the six numbers is same, i.e.

P (1) = P (2) = P (3) = P (4) = P (5) = P (6) = $\frac{1}{6}$

The expected pay for rolling the numbers are as follows:

E (X = 1) = $3

E (X = 2) = $0

E (X = 3) = $0

E (X = 4) = $0

E (X = 5) = $0

E (X = 6) = $4

The expected value of an experiment is:

$E(X)=\sum x\cdot P(X=x)$

Compute the expected monetary value of a single roll as follows:

$E(X)=\sum x\cdot P(X=x)\\=[E(X=1)\times \frac{1}{6}]+[E(X=2)\times \frac{1}{6}]+[E(X=3)\times \frac{1}{6}]\\+[E(X=4)\times \frac{1}{6}]+[E(X=5)\times \frac{1}{6}]+[E(X=6)\times \frac{1}{6}]\\=[3\times \frac{1}{6}]+[0\times \frac{1}{6}]+[0\times \frac{1}{6}]\\+[0\times \frac{1}{6}]+[0\times \frac{1}{6}]+[4\times \frac{1}{6}]\\=1.17$