Answer:
Neither parallel nor perpendicular
Step-by-step explanation:
I'm assuming you meant line k is y = 3x -2. If not, this is wrong.
For this, you need to put both lines in point-slope form, or the form that line k is already in. This means you only need to convert line m.
-2r + 6v = 18
6v = 2r + 18
v = 2/6r + 18/6
v = 1/3r + 3
Now you can answer the question.
To be parallel, lines must have the same slope (but a different y-intercept). 3 and 1/3 are not the same, so the lines are not parallel.
To be perpendicular, one line must have the opposite reciprocal (fraction flipped and + goes to - or - to +) of the other. While 3 is the reciprocal of 1/3, they are both positive, so they are not perpendicular.
To be the same line, the equations must be absolutely identical, which they aren't.
This leaves the last option: neither.
Let me know if you need a more in-depth explanation of anything here! I'm happy to help!
- 5z^3 - z^4 + 4z^5 is the answer.
Hey there!!
What is slope-intercept form :
... y = mx + b
( a ) Given :
... ( 2 , -2 ) and slope=1.4
... y = mx + b
... -2 = 2×1.4 + b
... -2 = 2.8 + b
... -4.8 = b
The slope-intercept form :
... y = 1.4x - 4.8
( b ) Given :
... ( -1 , 4 ) and slope = -3.
y = mx + b
... 4 = -3×-1 + b
... 4 = 3 + b
... 1 = b
The slope-intercept form :
... y = -3x + 1
Note :
( m = slope and b = y-intercept )
Hope my answer helps!!
Answer:
Step-by-step explanation:
t ÷ 5/12 = -3/10
t * 12/5 = -5/10
![t=\frac{-3*5}{10*12}\\\\t=\frac{-1*1}{2*4}\\\\t=\frac{-1}{8}](https://tex.z-dn.net/?f=t%3D%5Cfrac%7B-3%2A5%7D%7B10%2A12%7D%5C%5C%5C%5Ct%3D%5Cfrac%7B-1%2A1%7D%7B2%2A4%7D%5C%5C%5C%5Ct%3D%5Cfrac%7B-1%7D%7B8%7D)