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JulijaS [17]
3 years ago
6

The basketball team has 50 members, and 18 of them are 6th graders. What percentage of the team is in the 6th grade?​

Mathematics
2 answers:
motikmotik3 years ago
8 0

Answer:

36%

Step-by-step explanation:

\frac{18}{50} = \frac{36}{100}

So 36% of the team is in 6th grade.

Ostrovityanka [42]3 years ago
3 0

<em>Answer: </em><u><em>36%</em></u><em>. one hundred divided by two equals fifty, eighteen multiplied by two equals </em><u><em>36%</em></u><em>, therefore, its </em><u><em>36%</em></u>

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seropon [69]

Formula for this case is

(a+b)∧3=a∧3+3a∧2b+3ab∧2+b∧3

(2x+5)∧3=(2x)∧3+3*(2x)∧2*5+3*2x*5∧2+5∧3=8 x∧3+3*4x∧2*5+3*2x*25+125=

=8x∧3+60x∧2+150x+125

Good luck!!!

5 0
4 years ago
Which algebraic expression is equivalent to the expression below?
noname [10]

Answer:

I think that the correct answer is B. 29k + 4

8 0
3 years ago
If the heights of 300 students are normally distributed with mean 68.0 inches and standard deviation 3.0 inches, how many studen
Lunna [17]
Given:
μ = 68 in, population mean
σ = 3 in, population standard deviation

Calculate z-scores for the following random variable and determine their probabilities from standard tables.

x = 72 in:
z = (x-μ)/σ = (72-68)/3 = 1.333
P(x) = 0.9088

x = 64 in:
z = (64 -38)/3 = -1.333
P(x) = 0.0912

x = 65 in
z = (65 - 68)/3 = -1
P(x) = 0.1587

x = 71:
z = (71-68)/3 = 1
P(x) = 0.8413

Part (a)
For x > 72 in, obtain
300 - 300*0.9088 = 27.36

Answer: 27

Part (b)
For x ≤ 64 in, obtain
300*0.0912 = 27.36

Answer: 27

Part (c)
For 65 ≤ x ≤ 71, obtain
300*(0.8413 - 0.1587) = 204.78

Answer: 204

Part (d)
For x = 68 in, obtain
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P(x) = 0.5
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3 0
3 years ago
Which weights more 2.48 or 2.5​
Mazyrski [523]
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6 0
3 years ago
Arectangularplotoflandistobefencedinusingtwokinds of fencing. Two opposite sides will use heavy-duty fencing selling for $3 a fo
svlad2 [7]

Answer:

Dimensions of the rectangular plot will be 500 ft by 750 ft.

Step-by-step explanation:

Let the length of the rectangular plot = x ft.

and the width of the plot = y ft.

Cost to fence the length at the cost $3.00 per feet = 3x

Cost to fence the width of the cost $2.00 per feet = 2y

Total cost to fence all sides of rectangular plot = 2(3x + 2y)

2(3x + 2y) = 6,000

3x + 2y = 3,000 ----------(1)

3x + 2y = 3000

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Now area of the rectangle A = xy square feet

A = x[1500-\frac{3x}{2}]

For maximum area \frac{dA}{dx}=0

A' = \frac{d}{dx}(1500x-\frac{3}{2}x^{2}) = 0

1500 - 3x = 0

3x = 1500

x = 500 ft

From equation (1),

y = 1500 - \frac{3}{2}\times 500

y = 1500 - 750

y = 750 ft

Therefore, for the maximum area of the rectangular plot will be 500 ft × 750 ft.

two fencing 3(500+500) = $3000

other two fencing 2(750+750) = $3000

8 0
4 years ago
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