Answer:
q = 
c = 
Step-by-step explanation:
First solve for q:
0.162q + 0.035c = 4
0.162q = 4 - 0.035c (move term to other side)
q =
(divide both sides by 0.162 to get it away from q)
q =
(simplify fraction)
Solve for c:
0.162q + 0.035c = 4
0.035c = 4 - 0.162q (move term to other side)
c =
(divide both sides by 0.035 to get it away from c)
c =
(simplify fraction)
The lottery game is an illustration of probability
- The total number of different selections is 1000
- The probability of winning is 0.001
- The net profit of winning is $262.82
- The expected earning is -$1.156
<h3>The number of selections</h3>
Each of the three selections can be any of the 1o digits 0 - 9.
So, the total number of different selections is:


<h3>The probability of winning</h3>
Only one of the 1000 selections can win.
So, the probability of winning is:


<h3>The net profit</h3>
The stake amount is given as $1.42, and the earnings per game is given as $264.25.
So, the net profit is:
Net = $264.25 - $1.42
Net = $262.82
<h3>The expected winnings</h3>
This is calculated as:

So, we have:


Hence, the expected earning is -$1.156
Read more about probability at:
brainly.com/question/25870256
Answer:
Jeannette's ticket was less than the original pice by 30%
Step-by-step explanation:
original price = $75
percentage discount = 20% of original price = 20% of $75
discounted price = 
discounted price = $15
website service fee = 10% of original price
website service fee = 
New discounted price = discount price + website service fee
= 15 + 7.5 = $22.5
Next, let us calculate what percentage of the original price that will give the new discount price.
Let the percentage of the original price = x%
x% of 75 = $22.5

Therefore, Jeannette's ticket was less than the original pice by 30%
2 circles and for the part in the middle if you look at it as a net it
will be a rectangle just rolled up. That is called a lateral surface or a
lateral face
(x-h)^2 + (y-k)^2 = r^2
r=3
(x-h)^2 + (y-k)^2 = 3^2
the center lies on the y-axis --> h=0
x^2 + (y-k)^2 = 3^2 = 9
expand
x^2 + y^2 -2ky + k^2 = 9
x^2 + y^2 -2ky + (k^2 - 9) = 0
compare to general form
A=1 , B=1 and C =0
D= -2k and E=k^2 - 9