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ki77a [65]
3 years ago
11

I didn’t understand I’m freaking out over here can anybody help please

Mathematics
1 answer:
777dan777 [17]3 years ago
7 0

In our first equation, we can notice:

(x^m*x^2)=x^{2+m}

and

(x^{m+2})^3*k^{15}=x^{21} *k^{15} \implies \\ x^{m+2}=x^{21}

So, using the fact that x^{y}=x^z \implies y=z, we have:

m+2=21 \implies\\ m=19

In our second equation, we have:

(x^3*y^2)(\frac{x^2y^3*z^m}{z^{-5}})=x^5y^5z

So, using the exponent rules, we get:

(x^3*y^2)(\frac{x^2y^3*z^m}{z^{-5}})=\\ x^{2+3}*y^{3+2}*z^{m-(-5)}=\\x^5*y^5*z^{m+5}

So, we can cross out the common factors in each to give us:

z^{m+5}=z \implies\\ z^{m+5}=z^1 \implies \\ m+5=1 \implies \\ m=-4

So, using the exponent rules, we found the m values in both equations.


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Answer:

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Information provided

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Replacing the info given we got:

z=\frac{0.384-0.362}{\sqrt{0.374(1-0.374)(\frac{1}{4276}+\frac{1}{3908})}}=2.055    

The p value can be calculated from the alternative hypothesis with this probability:

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