Question

.162q + .035c = 4 Solve for q and c and show work

Answer 1

Answer:

q = $\frac{5(-7c+800)}{162}$

c = $\frac{2(-81q + 2000)}{35}$

Step-by-step explanation:

First solve for q:

0.162q + 0.035c = 4

0.162q = 4 - 0.035c (move term to other side)

q = $\frac{4-0.035c}{0.162}$ (divide both sides by 0.162 to get it away from q)

q = $\frac{5(-7c+800)}{162}$ (simplify fraction)

Solve for c:

0.162q + 0.035c = 4

0.035c = 4 - 0.162q (move term to other side)

c = $\frac{4 - 0.162q}{0.035}$ (divide both sides by 0.035 to get it away from c)

c = $\frac{2(-81q + 2000)}{35}$ (simplify fraction)