<h3> given:</h3>
<u>
</u>
<u>
</u>
<h3>to find:</h3>
the radius of the cone.
<h3>solution:</h3>
<u>hence</u><u>,</u><u> </u><u>the</u><u> </u><u>radius</u><u> </u><u>of</u><u> </u><u>the</u><u> </u><u>given</u><u> </u><u>cone</u><u> </u><u>is</u><u> </u><u>5.05</u><u> </u><u>centimeters</u><u>.</u>
Answer:
5x+8y
Step-by-step explanation:
We can first open the brackets by using the distrubitive propety.
2(x+4y)+3x
2x+8y+3x
Now we can combine like terms.
5x+8y.
I combined the 3x and the 2x. This works because imagined I have 3 of something then I got 2 more of that something I would now have 5 of that something.
Hoped this helped,
JoeLouis2
Answer:
{3, 4}
Step-by-step explanation:
"M(x)=(2x-6)(x-4) true statements when M(x)=0 when x= ?" asks us to find the "roots" of M(x); that is, the x values at which M(x) = 0. Thus, we set
(2x - 6)(x - 4) = 0, which is equivalent to 2(x - 3)(x - 4) = 0.
Thus, x - 3 = and x = 3; also x - 4 = 0, so that x = 4.
The roots of M(x) are {3, 4}
Using the language of the original problem: "true statements when M(x)=0 when x=" the correct results, inserted into the blanks, are x = 3 and x = 4.
If M is a midpoint of PQ, then we can use the formula of a midpoint:
We have the endpoints (-2a, 0) and (0, 2b). Substitute:
<h3>Answer: M(-a, b)</h3>
Answer:
A: the data is skewed to the right and shows that she never scored fewer than 2 points or more than 12 points in a game
Step-by-step explanation:
