What does the a equal in a/20=10
1 answer:
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Answer:
8x² +36x -27=0
Step-by-step explanation:
2x²= 6x +3
Let's rewrite the equation into the form of ax²+bx+c= 0.
2x² -6x -3=0
Thus, a= 2
b= -6
c= -3
Sum of roots=
Since your roots are p and q, sum of roots= p +q
p +q=
p +q= 6 ÷2
p +q= 3
Product of roots=
pq=
<u>Quadratic equations</u><u>:</u>
x² -(sum of roots)x +(product of roots)= 0
Thus, we have to find the sum and the product of the new roots, p²q and pq².
p +q= 3
pq= -3/2
Product of new roots
= (p²q)(pq²)
= p³q³
= (pq)³
sum of new roots
= p²q +pq²
= pq(p +q)
= (-3/2)(3)
= -9/2
Thus, the quadratic equation with roots p²q and pq² is
x² -(-9/2)x -27/8 = 0
Multiply by 8 throughout:
Answer:
No
Step-by-step explanation:
you can check with the pythagorean theory
64 + 81 = 144
145 = 144
this is not true, therefore those side lengths do not make a right triangle.
We can rewrite a cube root into a fractional index form.
So, we can rewrite:
![\sqrt[3]{m^{2}n^{5}} = (m^{2}n^{5})^{\frac{1}{3}](https://tex.z-dn.net/?f=%5Csqrt%5B3%5D%7Bm%5E%7B2%7Dn%5E%7B5%7D%7D%20%3D%20%28m%5E%7B2%7Dn%5E%7B5%7D%29%5E%7B%5Cfrac%7B1%7D%7B3%7D)
So, we can rewrite: