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3 years ago

If a line falls on the points (3, 1) and (9,5), what is its slope? Enter your

Mathematics

1 answer:

Anvisha [2.4K]3 years ago

7 0

<h3>Answer: 2/3</h3>

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Use the slope formula to get that answer

m = (y2-y1)/(x2-x1)

m = (5-1)/(9-3)

m = 4/6

m = 2/3

We have a rise of 2 and a run of 3.

In other words, we move up 2 and over to the right 3.

You might be interested in

Write the equation of the parabola with a focus at (-3, -5) and a directrix at y = -7.

lilavasa [31]

Answer:

The directrix is negative so the equation will be

x^2=4ay

x=-3

y=-5

a=x^2/4y

a=(-3)^2 /4*(-5)

a=9/20

x^2=4*(9/20)*y

x^2=9/5y

Step-by-step explanation:

The directrix always determine the equation to use. It is also important to notice the sign(-+).

3 0

3 years ago

Prove:<br> tan 70° = tan 20° + 2tan 50°

Natali5045456 [20]

As we all know,
According to the trigonometric identity,
tan70=tan(20+50)
tan70=(tan20+tan50)/1-tan20tan50
tan70-tan20tan50tan70=tan20+tan50
Also tan70tan20=tan70cot70=1
Hence
tan70-tan50=tan20+tan50
So tan70=tan20+2tan50
Hope this helps :) :)

7 0

4 years ago

Read 2 more answers

Please I need help it’s an emergency

Hunter-Best [27]

Answer:

A. $4\sqrt{6}$

Step-by-step explanation:

Applying the leg rule which is:

$\frac{Hypotenuse}{leg} = \frac{leg}{part}$

Hypotenuse = 4 + 8 = 12

Leg = x

Part = 8

Plug in the values

$\frac{12}{x} = \frac{x}{8}$

Cross multiply

$x*x = 8*12$

$x^2 = 96$

$\sqrt{x^2} = \sqrt{96}$

$x = \sqrt{16 * 6}$

$x = 4\sqrt{6}$

6 0

3 years ago

The standard deviation for actuary salaries has a standard deviation of $36,730 . You collect a simple random sample of n=36 sal

Yanka [14]

Using the z-distribution, it is found that the lower limit of the 95% confidence interval is of $99,002.

<h3>What is a z-distribution confidence interval?</h3>

The confidence interval is:

$\overline{x} \pm z\frac{\sigma}{\sqrt{n}}$

In which:

$\overline{x}$ is the sample mean.

z is the critical value.

n is the sample size.

$\sigma$ is the standard deviation for the population.

In this problem, we have a 95% confidence level, hence $\alpha = 0.95$ , z is the value of Z that has a p-value of $\frac{1+0.95}{2} = 0.975$ , so the critical value is z = 1.96.