Answer: he invested $15000 in part 1 and $60000 in part 2
Step-by-step explanation:
Let x represent the amount of money invested in part one.
Let 4x represent the amount of money invested in part 2 .
Total amount of money invested in part 1 and part 2 is
x + 4x = 5x
The formula for simple interest is expressed as
I = PRT/100
Where
P is the principal or initial amount.
T is the duration in years
R is the number rate.
For part 1
R = 7%
T = 1 year
P = x
I = (x × 7 × 1)/100 = 0.07x
For part 2,
R = 11%
T = 1 year
P = 4x
I = (4x × 11 × 1)/100 = 0.44x
if the total annual income from interest is 7650. This means that
0.44x + 0.07x = 7650 - - - - - - - -2
0.51x = 7650
x = 7650/0.51
x = 15000
Amount invested in part 1 is $15000
Amount invested in part 2 is 4×15000 = $60000
You would do 196 divided by 1/2. You would get: 392
For these problems, all we have to do is find the value of the variables
7. r + 354 = 1,321
All we need to do is subtract 1,321 and 354
1,321 - 354 = 967
r = 967
8. d - 21.4 = 87.9
All we need to do is add 87.9 and 21.4
89.7 + 21.4 = 111.1
d = 111.1
9. 5 x g = 230
All we need to do is divide 230 by 5
230 ÷ 5 = 46
g = 46
10. z ÷ 12 = 9
All we have to do is multiply 12 and 9
12 x 9 = 108
z = 108
Hope this helps you
-AaronWiseIsBae
Using the combination formula:
n! / (r!(n-r)!)
Where n is the number of people = 12 and r is the number of jurors = 9.
12! / (9!(12-9)!) = 220 combinations.
