Question

The perimeter of a rectangle is 54 meter. The difference of the length and the width is 11 meters. Find the dimensions of the rectangle

Answer 1

Let, length of the rectangle = (k) m

∴ Width becomes = (k - 11) m

We know, perimeter of a rectangle = 2(l + b)

∴ 2(l + b) = 54

⇒ (k) + (k - 11) = 27

⇒ 2k = 27 + 11 = 38

⇒ k = 19

∴ Dimensions = (k)(k - 11) = 19 m × 8 {answer}.