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2 years ago

A line passes through the points (5,22) and (7,24). Write a linear function rule in terms of x and y

Mathematics

1 answer:

nikdorinn [45]2 years ago

4 0

It 20 because it is and you multiply

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Kaltlin bought some books for $6 each and received a discount of $8 off of her total purchase. She spent $58 after the discount.

MrRissso [65]

Answer:

I might have bought about 9 books

4 0

2 years ago

Read 2 more answers

The set of life spans of an appliance is normally distributed with a mean mu = 48 months and a standard deviation sigma = 8 mont

navik [9.2K]

Using the normal distribution, it is found that the life span of an appliance that has a z-score of –3 is of 24 months.

<h3>Normal Probability Distribution</h3>

The z-score of a measure X of a normally distributed variable with mean $\mu$ and standard deviation $\sigma$ is given by:

$Z = \frac{X - \mu}{\sigma}$

The z-score measures how many standard deviations the measure is above or below the mean.

Looking at the z-score table, the p-value associated with this z-score is found, which is the percentile of X.

In this problem, the parameters are given as follows:

$\mu = 48, \sigma = 8, Z = -3$ .

Hence:

$Z = \frac{X - \mu}{\sigma}$

$-3 = \frac{X - 48}{8}$

X - 48 = -24

X = 24.

The life span of an appliance that has a z-score of –3 is of 24 months.

More can be learned about the normal distribution at brainly.com/question/24663213

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6 0

1 year ago

if a chocolate cake is divided into six equal and each has 280 calories, how many calories are in the whole cake

Contact [7]

Answer:

1680

Step-by-step explanation:

280 x 6 = 1680

3 0

2 years ago

If f(x) = <img src="https://tex.z-dn.net/?f=%5Cfrac%7B1%7D%7B9%7D" id="TexFormula1" title="\frac{1}{9}" alt="\frac{1}{9}" align=

boyakko [2]

Answer:

Solution given:

f(x) = $\frac{1}{9}$ x-2

let f(x)=y

y = $\frac{1}{9}$ x-2

interchanging role of x and y

x= $\frac{1}{9}$ y-2

x+2= $\frac{1}{9}$ y

y=9(x+2)

y=9x+18

F-¹(x)=9x+18

and

F-¹(-1)=9*-1+18=-9+18=9

6 0

2 years ago

Simplify the expression

kow [346]

Answer:

Step-by-step explanation:

$\dfrac{5x^3-8x^2-4x}{6x^2-18x+12}\\\\6(x^2-3x+2)\ne0\ \iff\ x=\frac{3\pm\sqrt{9-8}}{2}\ne0\ \iff\ x\ne2\ \wedge\ x\ne1\\\\\\\dfrac{5x^3-8x^2-4x}{6x^2-18x+12}=\dfrac{x(5x^2-8x-4)}{6(x^2-3x+2)}=\dfrac{x(5x^2-10x+2x-4)}{6(x^2-2x-x+2)}=\\\\\\=\dfrac{x[5x(x-2)+2(x-2)]}{6[x(x-2)-(x-2)]} =\dfrac{x(x-2)(5x+2)}{6(x-2)(x-1)}=\dfrac{x(5x+2)}{6(x-1)}=\dfrac{5x^2+2x}{6x-6}\\\\\\f(x)=5x^2+2x\\\\g(x)=6x-6$

4 0

2 years ago