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Ugo [173]
3 years ago
14

Subtract 5-3 1/3 fraction

Mathematics
1 answer:
AleksAgata [21]3 years ago
4 0
5 = 15/3

3 1/3 = 10/3

15/3 - 10/3 = 5/3

so 5-3 1/3 is either 5/3 or 1 2/3.
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Maths easy class 8 whoever gets it I will give u brainlist​
asambeis [7]

Answer:

424 cm²

Step-by-step explanation:

The figure is composed of a square and a trapezium on top

A of square = 18² = 324 cm²

A of trapezium = \frac{1}{2} h (b₁ + b₂ )

where h is the perpendicular height and b₁, b₂ the parallel bases

Here h = 8, b₁ = 18 and b₂ = 7 , then

A = 0.5 × 8 × (18 + 7) = 4 × 25 = 100 cm²

Area of hexagonal park = 324 + 100 = 424 cm²

8 0
2 years ago
Records indicate that for parts coming out a hydraulic repair shop at an airplane rework facility, 30\% will have a shaft defect
mrs_skeptik [129]

Answer:

P(A|B) = P(A∩B)/P(B) = 100%

Which means that there is 100% probability that the item has at least one type of defect given that the item has only a shaft defect.

Step-by-step explanation:

Conditional probability P(A|B) can be expressed as;

P(A|B) = P(A∩B)/P(B) .....1

Given;

30% will have a shaft defect,

15% will have a bushing defect,

and 65% will be defect-free

Total probability = 100% = P(shaft or/and bushing defect) + P(defect free)

P(shaft or/and bushing defect) = 100% - P(defect free)

= 100% - 65% = 35%

And

P(shaft or/and bushing defect) = P(shaft def only) + P(bushing def only) + P(shaft and bushing defect)

P(shaft or/and bushing defect) = P(shaft defect) + P(bushing defect) - P(shaft and bushing defect)

Substituting the values we have;

35% = 30% + 15% - P(shaft and bushing defect)

P(shaft and bushing defect) = 45% - 35% = 10%

Let A="The item has at least one type of defect"; and B="The item has only a shaft defect".

P(A) = P(shaft or/and bushing defect) = 35%

P(B) = P(shaft only defect) = 30% - 10% = 20%

P(A∩B) = 20%

Substituting into equation 1

P(A|B) = P(A∩B)/P(B) = 20%/20%

P(A|B) = 1/1 = 100%

Which means that there is 100% probability that the item has at least one type of defect given that the item has only a shaft defect.

5 0
3 years ago
Which example describes area
Aleks [24]
I believe C. Measuring the length from one end of the field tot he other would be the most reasonable answer, because Area = Length x Width
6 0
3 years ago
Math quick i need help hurry 15 points :)
schepotkina [342]

Answer:

B

Step-by-step explanation:

I don't know how to explain it but

10/2=5 (Driver A)

20/2= 10 (Driver B)

Sorry if it's not right

4 0
3 years ago
A gardener uses 1/3 of a liter of water to water 2/7 of a garden.
Serjik [45]

the gardener would need (1 + 1/6) liters of water to water the whole garden.

<h3>How much water would the gardener need to water the whole garden?</h3>

Here we know that the gardener needs 1/3 of a liter of water to water 2/7 of a garden.

Then we have the relation:

1/3 L = 2/7 of a garden.

Now, we want to get a "1 garden" in the right side of the equation, then we can multiply both sides by (7/2), so we get:

(7/2)*(1/3) L = (7/2)*(2/7) of a garden

(7/6)L = 1 garden.

(1 + 1/6) L = 1 garden

This means that the gardener would need (1 + 1/6) liters of water to water the whole garden.

If you want to learn more about fractions:

brainly.com/question/11562149

#SPJ1

5 0
1 year ago
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