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Ugo [173]
3 years ago
14

Subtract 5-3 1/3 fraction

Mathematics
1 answer:
AleksAgata [21]3 years ago
4 0
5 = 15/3

3 1/3 = 10/3

15/3 - 10/3 = 5/3

so 5-3 1/3 is either 5/3 or 1 2/3.
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How to simplify the following expression<br> 34x-(25x-3)-18
PilotLPTM [1.2K]

Answer: 9x-15

Step-by-step explanation:

Given

34x-(25x-3)-18

Expand parenthesis

34x-25x+3-18

Put like terms together

(34x-25x)+(3-18)

Combine like terms

9x-15

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2 years ago
Mr thompson wants to protect his garage by installing a flood barrier. He connects 2 barriers side by side. Each barrier is 9 ft
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Answer:

Step-by-step explanation:

Mr Thompson wants to protect his garage by installing a flood barrier. He connects 2 barriers side by side. The length of each flood barrier is 9 ft while the height of each barrier is 2 ft. The barriers are rectangular in shape. The area of each rectangular barrier is expressed as length × height.

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3 years ago
A survey asked 40 students if they play an instrument and if they 20 students are in band.
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3 years ago
A business organization needs to make up a 8 member fund-raising committee. The organization has 6 accounting majors and 6 finan
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Answer:

Total no of ways can the fund raising committee be formed if at least 4 accounting majors are on the committee. = 360

Step-by-step explanation:

Given  -  

A business organization needs to make up a 8 member fund-raising committee.

The organization has 6 accounting majors and 6 finance majors .

Total no of ways can the fund raising committee be formed if at least 4 accounting majors are on the committee.

(1) chose 4 accounting majors  from 6 and chose 4 finance  majors  from 6  =

  =   \binom{6}{4}\times\binom{6}{4}

 =  \frac{(6!)}{(2!)(4!)}\times \frac{(6!)}{(2!)(4!)} = 225

(2) chose 5 accounting majors  from 6 and chose 3 finance  majors  from 6 =  \binom{6}{5}\times\binom{6}{3}

=  \frac{(6!)}{(1!)(5!)}\times\frac{(6!)}{(3!)(3!)} = 120

=

(3) chose 6 accounting majors  from 6 and chose 2 finance  majors  from 6 = \binom{6}{6}\times \binom{6}{2}

= \frac{(6!)}{(6!)(0!)}\times\frac{(6!)}{(2!)(4!)} = 15

Then total no of ways = (1) + (2) + 3

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