Fastttt I have 2 more mins please someone answer

Mathematics

1 answer:

Musya8 [376]3 years ago

5 0

Answer:

Step-by-step explanation:

is 50

360-230=130

180-130=50

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Can someone pls help me I’m so confused!!! :(

Naddika [18.5K]

Answer:

u = 150

Step-by-step explanation:

Number of vertices:

Find the sum of the interior angles:

180(n - 2)

180(10 - 2)

180(8)

1440

To find u:

u = 1440 - (130 + 145 + 160 + 150 + 130 + 150 + 125 + 155 + 145)

u = 1440 - (1290)

u = 150

4 0

3 years ago

Please help;-; tysm! (23 points)

avanturin [10]

Answer:

The answer is x = 27.

Step-by-step explanation:

<h2><u><em>PLEASE MARK AS BRAINLIEST!!!!!</em></u></h2>

5 0

3 years ago

If sin(x) = 5/13, and x is in quadrant 1, then tan(x/2) equals what?

Rufina [12.5K]

$x$ is in quadrant I, so $0$ , which means $0$ , so $\dfrac x2$ belongs to the same quadrant.

Now,

$\tan^2\dfrac x2=\dfrac{\sin^2\frac x2}{\cos^2\frac x2}=\dfrac{\frac{1-\cos x}2}{\frac{1+\cos x}2}=\dfrac{1-\cos x}{1+\cos x}$

Since $\sin x=\dfrac5{13}$ , it follows that

$\cos^2x=1-\sin^2x\implies \cos x=\pm\sqrt{1-\left(\dfrac5{13}\right)^2}=\pm\dfrac{12}{13}$

Since $x$ belongs to the first quadrant, you take the positive root ( $\cos x>0$ for $x$ in quadrant I). Then

$\tan\dfrac x2=\pm\sqrt{\dfrac{1-\frac{12}{13}}{1+\frac{12}{13}}}$

$\tan x$ is also positive for $x$ in quadrant I, so you take the positive root again. You're left with

$\tan\dfrac x2=\dfrac15$